Submission #1127853

#TimeUsernameProblemLanguageResultExecution timeMemory
1127853zhasynBank (IZhO14_bank)C++20
44 / 100
1095 ms432 KiB
#include <bits/stdc++.h> #define pb push_back #define pf push_front using namespace std; #define F first #define S second typedef long long ll; #define pii pair <int, int> #define pll pair <ll, ll> typedef long double ld; const ll N = 3 * 1e5 + 100, M = 500 + 10, len = 315, inf = 1e18; const ll mod = 998244353; ll um(ll a, ll b){ return (1LL * a * b) % mod; } ll subr(ll a, ll b){ return ((1LL * a - b) % mod + mod) % mod; } ll bp(ll x, ll step){ ll res = 1; while(step){ if(step & 1) res = um(res, x); x = um(x, x); step /= 2; } return res; } ll inv(ll x){ return bp(x, mod - 2); } int a[N], b[N], n, m, cnt[N]; void subtask1(){ bool can = false; for(int mask = 0; mask < (1 << m); mask++){ int cur = 0; for(int dig = 0; dig < m; dig++){ if((mask & (1 << dig)) > 0) cur += b[dig]; } if(cur == a[0]) can = true; } if(can) cout << "YES"; else cout << "NO"; } void subtask2(){ sort(b, b + m); bool tot = false; do { int from = 0, sm = 0; for(int i = 0; i < m; i++){ sm += b[i]; if(sm == a[from]){ from++; sm = 0; } if(from == n){ tot = true; break; } } } while(next_permutation(b, b + m) == 1); if(tot) cout << "YES"; else cout << "NO"; } void subtask3(){ for(int i = 0; i < n; i++){ cnt[a[i]]++; } int nx = n, mx = m; vector <int> vn, vm; for(int i = 0; i < m; i++){ if(cnt[b[i]] > 0){ cnt[b[i]]--; nx--; mx--; } else vm.pb(b[i]); } for(int i = 0; i < n; i++){ if(cnt[a[i]] > 0){ vn.pb(a[i]); cnt[a[i]]--; } } if(mx/2 < nx){ cout << "NO"; return; } sort(vm.begin(), vm.end()); bool tot = false; do { int from = 0, sm = 0; for(int i = 0; i < mx; i++){ sm += vm[i]; if(sm == vn[from]){ from++; sm = 0; } if(from == nx){ tot = true; break; } } } while(next_permutation(vm.begin(), vm.end()) == 1); if(tot) cout << "YES"; else cout << "NO"; } int main() { //ios_base::sync_with_stdio(false); //cin.tie(nullptr); //cout.tie(nullptr); cin >> n >> m; for(int i = 0; i < n; i++){ cin >> a[i]; } for(int i = 0; i < m; i++){ cin >> b[i]; } //subtask3(); if(n == 1) subtask1(); else{ if(m <= 10) subtask2(); else subtask3(); } return 0; }
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