제출 #1127086

#제출 시각아이디문제언어결과실행 시간메모리
1127086kingmessiPotatoes and fertilizers (LMIO19_bulves)C++20
100 / 100
200 ms33952 KiB
// Har Har Mahadev #include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> // Common file #include <ext/pb_ds/tree_policy.hpp> #define ll long long #define int long long #define rep(i,a,b) for(int i=a;i<b;i++) #define rrep(i,a,b) for(int i=a;i>=b;i--) #define repin rep(i,0,n) #define precise(i) cout<<fixed<<setprecision(i) #define vi vector<int> #define si set<int> #define mii map<int,int> #define take(a,n) for(int j=0;j<n;j++) cin>>a[j]; #define give(a,n) for(int j=0;j<n;j++) cout<<a[j]<<' '; #define vpii vector<pair<int,int>> #define db double #define be(x) x.begin(),x.end() #define pii pair<int,int> #define pb push_back #define pob pop_back #define ff first #define ss second #define lb lower_bound #define ub upper_bound #define bpc(x) __builtin_popcountll(x) #define btz(x) __builtin_ctz(x) using namespace std; using namespace __gnu_pbds; typedef tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> ordered_set; typedef tree<pair<int, int>, null_type,less<pair<int, int> >, rb_tree_tag,tree_order_statistics_node_update> ordered_multiset; const long long INF=1e18; const long long M=1e9+7; const long long MM=998244353; int power( int N, int M){ int power = N, sum = 1; if(N == 0) sum = 0; while(M > 0){if((M & 1) == 1){sum *= power;} power = power * power;M = M >> 1;} return sum; } const int MAXN = 100005; int Z = 1; int ls, rs, lv, zp; map<int, int> MP; void fix_left(ll s) { if (ls >= s) return; auto it = MP.begin(); while (ls + it->second <= s) { ls += it->second; lv += ls * (next(it)->first - it->first); MP.erase(it++); } it->second -= s - ls; ls = s; } void fix_right(ll s) { if (rs <= s) return; auto it = --MP.end(); while (rs - it->second >= s) { rs -= it->second; MP.erase(it--); } it->second += s - rs; rs = s; } void advance() { ll lo = MP.begin()->first; if (zp < lo) lv += ls * (zp - lo); else lv += Z * (zp - lo); ls -= Z, rs += Z; MP[zp] += 2 * Z; } void solve() { int n; cin >> n; vi a(n); vi b(n); vi d(n); int off = 0; repin{ cin >> a[i] >> b[i]; d[i] = a[i]-b[i]; if(i)d[i] += d[i-1]; } repin{ if(d[i] < 0)off -= d[i],d[i] = 0; } ls = -1; rs = 1; MP[d[0]] = 2; rep(i,1,n){ zp = d[i]; fix_left(-i); fix_right(0); advance(); } int fin = lv, s = ls; for (auto it = MP.begin(); it->first < zp; it++) { s += it->second; fin += s * (min(next(it)->first,d.back()) - it->first); } cout << fin+off << '\n'; } signed main(){ ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #ifdef NCR init(); #endif #ifdef SIEVE sieve(); #endif solve(); return 0; }
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