제출 #1127038

#제출 시각아이디문제언어결과실행 시간메모리
1127038duckindogSeesaw (JOI22_seesaw)C++20
34 / 100
2098 ms75892 KiB
#include <bits/stdc++.h> using namespace std; #define double long double const int N = 2'000 + 10; const double MAX = 1e9; int n; int a[N]; long long pref[N]; inline long long sum(int l, int r) { return pref[r] - pref[l - 1]; } inline double cal(int l, int r) { return (double)sum(l, r) / (r - l + 1); } int way[N][N]; double f[N][N]; pair<int, int> par[N][N]; bool mk[N][N]; int32_t main() { cin.tie(0)->sync_with_stdio(0); cin >> n; for (int i = 1; i <= n; ++i) cin >> a[i]; for (int i = 1; i <= n; ++i) pref[i] = pref[i - 1] + a[i]; for (int i = 1; i <= n; ++i) { for (int j = 1; j <= n; ++j) f[i][j] = MAX; } f[1][n] = cal(1, n); using TP = tuple<double, int, int>; priority_queue<TP, vector<TP>, greater<>> q; double answer = MAX; auto go = [&](int x, int y) { if (!x && !y) return; double mi = MAX; while (x != y) { f[x][y] = max(f[x][y], cal(x, y)); if (!mk[x][y]) q.emplace(cal(x, y), x, y), mk[x][y] = true; mi = min(mi, cal(x, y)); int nX = (!way[x][y] ? x : x + 1), nY = (!way[x][y] ? y - 1 : y); f[nX][nY] = f[x][y]; par[nX][nY] = {x, y}; tie(x, y) = {nX, nY}; } f[x][y] = max(f[x][y], cal(x, y)); if (!mk[x][y]) q.emplace(cal(x, y), x, y), mk[x][y] = true; mi = min(mi, cal(x, y)); answer = min(answer, f[x][y] - min(cal(1, n), get<0>(q.top()))); }; go(1, n); while (q.size()) { auto [d, i, j] = q.top(); q.pop(); auto [x, y] = par[i][j]; if (way[x][y]) continue; way[x][y] = 1; go(x, y); } cout << setprecision(9) << fixed << answer << "\n"; }
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