제출 #1126260

#제출 시각아이디문제언어결과실행 시간메모리
1126260kingmessiPotatoes and fertilizers (LMIO19_bulves)C++20
0 / 100
288 ms35604 KiB
// Har Har Mahadev #include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> // Common file #include <ext/pb_ds/tree_policy.hpp> #define ll long long #define int long long #define rep(i,a,b) for(int i=a;i<b;i++) #define rrep(i,a,b) for(int i=a;i>=b;i--) #define repin rep(i,0,n) #define precise(i) cout<<fixed<<setprecision(i) #define vi vector<int> #define si set<int> #define mii map<int,int> #define take(a,n) for(int j=0;j<n;j++) cin>>a[j]; #define give(a,n) for(int j=0;j<n;j++) cout<<a[j]<<' '; #define vpii vector<pair<int,int>> #define db double #define be(x) x.begin(),x.end() #define pii pair<int,int> #define pb push_back #define pob pop_back #define ff first #define ss second #define lb lower_bound #define ub upper_bound #define bpc(x) __builtin_popcountll(x) #define btz(x) __builtin_ctz(x) using namespace std; using namespace __gnu_pbds; typedef tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> ordered_set; typedef tree<pair<int, int>, null_type,less<pair<int, int> >, rb_tree_tag,tree_order_statistics_node_update> ordered_multiset; const long long INF=1e18; const long long M=1e9+7; const long long MM=998244353; int power( int N, int M){ int power = N, sum = 1; if(N == 0) sum = 0; while(M > 0){if((M & 1) == 1){sum *= power;} power = power * power;M = M >> 1;} return sum; } void solve() { int n; cin >> n; vi a(n),b(n); vi d(n); repin{ cin >> a[i] >> b[i]; d[i] = a[i]-b[i]; if(i)d[i] += d[i-1]; } int ans = 0; repin{ //since minimum element must be greater than zero if(d[i] < 0)ans -= d[i],d[i] = 0; } multiset<int> ms; rep(i,0,n-1){ ms.insert(d[i]); auto it = ms.end(); it--; ans += (*it)-d[i]; ms.insert(d[i]); it = ms.end(); it--; ms.erase(it); } //finding ans at d.back() auto it = ms.end(); it--; int nx = (*it); ms.erase(it); if(d.back() >= nx){ cout << ans << "\n";return; } int cnt = 0; while(ms.size()){ auto it = ms.end(); it--; auto res = (*it); ms.erase(it); cnt++; if(d.back() >= res){ ans += (nx-d.back())*cnt; nx = 0; break; } ans += (nx-res)*cnt; nx = res; } if(nx-d.back()>0)ans += (nx-d.back())*cnt; cout << ans << "\n"; } signed main(){ ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #ifdef NCR init(); #endif #ifdef SIEVE sieve(); #endif solve(); return 0; }
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