Submission #1125859

#	Time	Username	Problem	Language	Result	Execution time	Memory
1125859		ntdaccode	Factories (JOI14_factories)	C++20	0 / 100	50 ms	47680 KiB

factories

#include<bits/stdc++.h>
#define fori(i,a,b) for(int i=a;i<=b;i++)
#define pb push_back


using namespace std;

typedef pair<long long,long long> ii;
typedef tuple<int,int,int> tp;

const int M = 1e6 + 10;
const int N = 1e3 + 10;
const int mod = 1e9 + 7;

int n, q;
vector<ii> ke[M];

int num[M], tail[M], cnt = 0, up[M][20];
long long d[M];
void dfs(int u,int p = 0)
{
  num[u] = ++ cnt;
  for(int i = 1;i <= 19; i++) up[u][i] = up[up[u][i - 1]][i - 1];
  for(ii tmp : ke[u]) {
    int v = tmp.first, w = tmp.second;
    if(v == p) continue;
    d[v] = d[u] + w;
    up[v][0] = u;
    dfs(v,u);
  }
  tail[u] = cnt;
}

bool anc(int u,int v)
{
  return num[u] <= num[v] && tail[u] >= tail[v];
}

int lca(int u,int v)
{
  if(anc(u,v)) return u;
  if(anc(v,u)) return v;
  for(int i = 19; i >= 0; i--) if(!anc(up[u][i],v)) u = up[u][i];
  return up[u][0];
}

long long dist(int u,int v)
{
  int x = lca(u,v);
  return d[u] + d[v] - 2 * d[x];
}

vector<ii> adj[M];
long long D[M];
bool cmp(const int &a,const int &b) {
  return num[a] < num[b];
}


void Init(int N, int A[], int B[], int D[]) {
  n = N;
  for(int i = 0;i < n - 1; i++) {
      int u = A[i], v = B[i], w = D[i];
      u ++, v ++;
      ke[u].pb({v,w});
      ke[v].pb({u,w});
  }
  up[1][0] = 1;
  dfs(1,0);
  for(int i = 1;i <= n; i++) D[i] = 1e9;
}

long long Query(int S, int X[], int T, int Y[]){
  vector<int> Q;
  for(int i = 0;i < S; i++) {
      int u = X[i];
      u++;
      Q.pb(u);
  }
  for(int i = 0;i < T; i++) {
      int u = Y[i];
      u++;
      Q.pb(u);
  }
      sort(Q.begin(), Q.end(),cmp);
    Q.resize(unique(Q.begin(), Q.end()) - Q.begin());
    int m = Q.size();
    for(int i = 1;i <= m - 1; i++) {
        Q.pb(lca(Q[i - 1],Q[i]));
        //cout << Q[i - 1] << " " << Q[i] << " " << lca(Q[i], Q[i - 1]) << "\n";
    }
    sort(Q.begin(), Q.end(), cmp);
    Q.resize(unique(Q.begin(), Q.end()) - Q.begin());
    stack<int> sk;
    for(int v : Q) {
      while(!sk.empty() && !anc(sk.top(),v)) sk.pop();
      if(!sk.empty()) {
          int w = dist(v,sk.top());
          adj[v].pb({sk.top(),w});
          adj[sk.top()].pb({v,w});
      }
      sk.push(v);
    }
    while(!sk.empty()) {
        int v = sk.top();sk.pop();
        if(!sk.empty()) {
        int w = dist(v,sk.top());
        adj[v].pb({sk.top(),w});
        adj[sk.top()].pb({v,w});
        }
    }
    priority_queue<ii, vector<ii>, greater<ii> > h;
    for(int i = 0;i < S; i++) {
        int v = X[i];
        D[v] = 0;
        h.push({0,v});
    }
    while(!h.empty()) {
      int u, val;
      tie(val,u) = h.top();h.pop();
      if(D[u] < val) continue;
      for(ii tmp : adj[u]) {
        int v = tmp.first, w = tmp.second;
        if(D[v] > D[u] + w) {
          D[v] = D[u] + w;
          h.push({D[v],v});
        }
      }
    }
    long long kq = 1e15;
    for(int i = 0;i < T; i++) kq = min(kq, D[Y[i]]);
    for(int v : Q) {
      adj[v].clear();
      D[v] = 1e15;
    }
    return kq;

}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 18
• Subtask 3: 0 / 67