제출 #1125641

#제출 시각아이디문제언어결과실행 시간메모리
1125641baoheyheyK개의 묶음 (IZhO14_blocks)C++17
100 / 100
290 ms83992 KiB
#include<bits/stdc++.h> #define ll long long #define FOR(i, l, r) for(int i = (l), _r = r; i <= _r; ++i) #define FOD(i, l, r) for(int i = (l), _r = r; i >= _r; --i) #define pb push_back #define ALL(a) a.begin(), a.end() #define el "\n" #define bit(a, x) (a >> x & 1) #define X first #define Y second #define TIME (1.0 * clock() / CLOCKS_PER_SEC) #define cntbit(x) __builtin_popcountll(x) #define uni(a) sort(ALL(a)), a.resize(unique(ALL(a)) - a.begin()) #define sz(a) a.size() using namespace std; typedef pair<int, int> pii; typedef pair<ll, ll> pll; typedef vector<int> vi; typedef vector<ll> vll; const int maxn = 1e5 + 5; ll dp[maxn][105]; ll n, a[maxn], k; int main(){ ios_base::sync_with_stdio(false); cin.tie(NULL); // #define task "task" // if(fopen(task".inp", "r")){ // freopen(task".inp", "r", stdin); // freopen(task".out", "w", stdout); // } cin >> n >> k; FOR(i, 1, n) cin >> a[i]; memset(dp, 0x3f, sizeof(dp)); dp[0][1] = 0; FOR(i, 1, n) dp[i][1] = max(dp[i - 1][1], a[i]); FOR(i, 2, k){ stack<pll> st; FOR(j, i, n){ ll minn = dp[j - 1][i - 1]; while(sz(st) && a[st.top().Y] <= a[j]){ minn = min(minn, st.top().X); st.pop(); } dp[j][i] = min(dp[(sz(st) ? st.top().Y : 0)][i], minn + a[j]); st.push({minn, j}); } } cout << dp[n][k]; cerr << "Time elapsed: " << TIME << " s" << el; }
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