제출 #1125562

#제출 시각아이디문제언어결과실행 시간메모리
1125562heeyXORanges (eJOI19_xoranges)C++20
0 / 100
123 ms6072 KiB
#include <bits/stdc++.h> using namespace std; const int maxn = 2e5 + 5; int n; int seg[4*maxn], sego[4*maxn]; int a[maxn], b[maxn]; void build(int v, int l, int r){ if(l == r) { seg[v] = a[l]; return; } int m = (l+r)>>1; build(v<<1, l, m); build(v<<1|1, m+1, r); seg[v] = seg[v<<1] ^ seg[v<<1|1]; } void update(int pos, int val, int nod, int tl, int tr){ if(tl == tr) { seg[nod] = val; a[pos] = val; return; } int m = (tl+tr)>>1; if(pos <= m) update(pos, val, nod<<1, tl, m); else update(pos, val, nod<<1|1, m+1, tr); seg[nod] = seg[nod<<1] ^ seg[nod<<1|1]; } int query(int l, int r, int nod, int tl, int tr){ if(tl > r || tr < l || tl > tr) return 0; if(tl >= l && tr <= r) return seg[nod]; int mid = (tl+tr)>>1; return query(l, r, nod<<1, tl, mid) ^ query(l, r, nod<<1|1, mid+1, tr); } void build2(int v, int l, int r){ if(l == r){ sego[v] = b[l]; return; } int m = (l+r)>>1; build2(v<<1, l, m); build2(v<<1|1, m+1, r); sego[v] = sego[v<<1] ^ sego[v<<1|1]; } void update2(int p, int v, int nod, int l, int r){ if(l == r){ sego[nod] = v; b[p] = v; return; } int m = (l+r)>>1; if(p <= m) update2(p, v, nod<<1, l, m); else update2(p, v, nod<<1|1, m+1, r); sego[nod] = sego[nod<<1] ^ sego[nod<<1|1]; } int query2(int l, int r, int nod, int tl, int tr){ if(tl > r || tr < l || tl > tr) return 0; if(tl >= l && tr <= r){ return sego[nod]; } int m = (tl+tr)>>1; return query2(l, r, nod<<1, tl, m) ^ query2(l, r, nod<<1|1, m+1, tr); } signed main(){ ios_base::sync_with_stdio(0); cin.tie(0); int n, q; cin >> n >> q; vector<int> nz(n+1); for(int i = 1; i <= n; i++) cin >> nz[i]; for(int i = 1; i <= n; i++){ if(i % 2 == 0) a[i/2] = nz[i]; else b[(i+1)/2] = nz[i]; } build(1, 1, n/2); build2(1, 1, (n+1)/2); for(int i = 0; i < q; i++){ int t; cin >> t; if(t == 1){ int p, v; cin >> p >> v; if(p % 2 == 0) update(p/2, v, 1, 1, n/2); else update2((p+1)/2, v, 1, 1, (n+1)/2); } else{ int l, r; cin >> l >> r; if(r - l + 1 % 2 == 0) cout << "0\n"; else if(l % 2 == 0) cout << query(l/2, r/2, 1, 1, n/2) << '\n'; else cout << query2((l+1)/2, (r+1)/2, 1, 1, (n+1)/2) << '\n'; } } return 0; }
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