Submission #112544

#TimeUsernameProblemLanguageResultExecution timeMemory
112544someone_aaCake 3 (JOI19_cake3)C++17
24 / 100
4074 ms208272 KiB
#include <bits/stdc++.h> #define ll long long #define pb push_back #define mp make_pair #define P pair<ll,ll> using namespace std; const int maxn = 200100; ll n, m, arr[maxn]; vector<P>v; struct node { public: node *lc, *rc; ll cnt; ll sum; node(ll _cnt, ll _sum) { lc = rc = NULL; cnt = _cnt; sum = _sum; } node(node *a, node *b) { sum = a->sum + b->sum; cnt = a->cnt + b->cnt; lc = a; rc = b; } }; ll val[maxn]; set<ll>st; map<ll,int>ind; node* pref[maxn]; node* build(int li=0, int ri=n) { if(li == ri) return new node(0LL, 0LL); else { int mid = (li + ri) / 2; return new node(build(li, mid), build(mid+1, ri)); } } node* insert_number(node *curr, int pos, int sum_val, int li=0, int ri=n) { if(li == ri) { return new node(curr->cnt+1, curr->sum+sum_val); } else { int mid = (li + ri) / 2; if(pos <= mid) return new node(insert_number(curr->lc, pos, sum_val, li, mid), curr->rc); else return new node(curr->lc, insert_number(curr->rc, pos, sum_val, mid+1, ri)); } } ll solve(node *l, node *r, int k, int li=0, int ri=n) { if(k == 0) return 0LL; ll total_cnt = r->cnt - l->cnt; ll total_sum = r->sum - l->sum; //cout<<"["<<li<<" "<<ri<<"] -> "<<total_cnt<<", "<<total_sum<<"\n"; if(k == total_cnt) return total_sum; if(li == ri) return k * val[li]; else { int mid = (li + ri) / 2; ll total = r -> rc -> cnt - l -> rc -> cnt; ll sum_total = r -> rc -> sum - l -> rc -> sum; if(total >= k) return solve(l->rc, r->rc, k, mid+1, ri); else return sum_total + solve(l->lc, r->lc, k-total, li, mid); } } int main() { cin>>n>>m; ll a, b; for(int i=0;i<n;i++) { cin>>a>>b; v.pb(mp(b, a)); st.insert(a); } sort(v.begin(), v.end()); int br = 0; for(ll i:st) { val[br] = i; ind[i] = br++; } node *root = build(); for(int i=1;i<=n;i++) { root = insert_number(root, ind[v[i-1].second], v[i-1].second); pref[i] = root; } ll result = LLONG_MIN; for(int i=1;i<=n;i++) { if(i < m) continue; //cout<<i<<": \n"; for(int j=i-1;j>=1;j--) { if(i-j+1<m) continue; ll sum = v[i-1].second + v[j-1].second; ll cost = 2*(v[i-1].first - v[j-1].first); //cout<<j<<": "<<sum<<" - "<<cost<<" with maximum elements "<<solve(pref[j], pref[i-1], m-2)<<"\n"; result = max(result, solve(pref[j], pref[i-1], m-2) + sum - cost); } } cout<<result<<"\n"; return 0; }
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