제출 #1124145

#제출 시각아이디문제언어결과실행 시간메모리
1124145ljtunasIzbori (COCI22_izbori)C++20
0 / 110
16 ms7096 KiB
// author : anhtun_hi , nqg // 25-26.12.2024 #include <bits/stdc++.h> #define fi first #define se second #define all(x) x.begin(), x.end() #define reset(h, v) memset(h, v, sizeof h) #define Forv(i, a) for(auto& i : a) #define For(i, a, b) for(int i = a; i <= b; ++i) #define Ford(i, a, b) for(int i = a; i >= b; --i) #define c_bit(i) __builtin_popcountll(i) #define Bit(mask, i) ((mask >> i) & 1LL) #define onbit(mask, i) ((mask) bitor (1LL << i)) #define offbit(mask, i) ((mask) &~ (1LL << i)) #define Log2(x) (63 - __builtin_clzll(x)) #define TIME (1.0 * clock() / CLOCKS_PER_SEC) using namespace std; using ll = long long; using ii = pair<ll, ll>; using db = long double; using ull = unsigned long long; namespace std { template <typename T, int D> struct _vector : public vector <_vector <T, D - 1>> { static_assert(D >= 1, "Dimension must be positive!"); template <typename... Args> _vector(int n = 0, Args... args) : vector <_vector <T, D - 1>> (n, _vector <T, D - 1> (args...)) {} }; template <typename T> struct _vector <T, 1> : public vector <T> { _vector(int n = 0, const T& val = T()) : vector <T> (n, val) {} }; template <class A, class B> bool minimize(A &a, B b){return a > b ? a = b, true : false;} template <class A, class B> bool maximize(A &a, B b){return a < b ? a = b, true : false;} } const int dx[] = {0, 0, +1, -1}, dy[] = {-1, +1, 0, 0}, LOG = 20, base = 311, inf = 1e9 + 5; const int MAXN = 2e5 + 5, Block = 445; const ll mod = 1e9 + 7; const ll oo = 1e18; //#define int long long int n, a[MAXN]; vector<int> List[MAXN]; ll f[MAXN]; struct Fenwick{ int bit[MAXN]; void update(int u, int val){ ++u; while(u) bit[u] += val, u -= u &- u; } int get(int u){ ++u; int res = 0; while (u <= n + 1) res += bit[u], u += u &- u; return res; } int get(int l, int r){ return get(l) - get(r + 1); } } T[450]; ll Sum = 0; ll lazy[MAXN]; void add(int i){ if (lazy[i / Block] != 0){ for (int j = i; j <= n, j / Block == i / Block; ++j){ T[i / Block].update(f[j], -1); T[i / Block].update(f[j] + lazy[i / Block], +1); } for (int j = i - 1; j >= 1, j / Block == i / Block; --j){ T[i / Block].update(f[j], -1); T[i / Block].update(f[j] + lazy[i / Block], +1); } lazy[i / Block] = 0; } For(j, 1, i / Block - 1) Sum -= T[j].get(1, f[j] - 1 - lazy[j]); For(j, 1, i / Block - 1) Sum += T[j].get(1, f[j] + 2 - 1 - lazy[j]); For(j, i / Block + 1, n / Block) lazy[j] += 2; } void del(int i){ if (lazy[i / Block]){ for (int j = i; j <= n, j / Block == i / Block; ++j){ T[i / Block].update(f[j], -1); T[i / Block].update(f[j] + lazy[i / Block], +1); } for (int j = i - 1; j >= 1, j / Block == i / Block; --j){ T[i / Block].update(f[j], -1); T[i / Block].update(f[j] + lazy[i / Block], +1); } lazy[i / Block] = 0; } For(j, 1, i / Block - 1) Sum -= T[j].get(1, f[j] - 1 - lazy[j]); For(j, 1, i / Block - 1) Sum += T[j].get(1, f[j] - 2 - 1 - lazy[j]); For(j, i / Block + 1, n / Block) lazy[j] -= 2; } void Solve() { cin >> n; vector<int> compress; For(i, 1, n) cin >> a[i], compress.push_back(a[i]); sort(all(compress)); For(i, 1, n) { a[i] = lower_bound(all(compress), a[i]) - compress.begin() + 1; List[a[i]].push_back(i); } // For(i, 1, n) f[i] = f[i - 1] - 1, T[i / Block].update(f[i], 1); For(u, 1, n){ } } signed main() { cin.tie(0) -> sync_with_stdio(0); if(fopen("a.inp", "r")) { freopen("a.inp", "r", stdin); freopen("a.out", "w", stdout); } int t = 1; // cin >> t; while(t --) Solve(); return 0; }

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'int main()':
Main.cpp:121:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  121 |         freopen("a.inp", "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~
Main.cpp:122:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  122 |         freopen("a.out", "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~
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