Submission #1122964

#TimeUsernameProblemLanguageResultExecution timeMemory
1122964Mamikonm1Bank (IZhO14_bank)C++17
100 / 100
270 ms8872 KiB
#include <iostream> #include <vector> #include <cmath> #include <algorithm> #include <map> #include <iomanip> #include <string> #include <set> #include <queue> using namespace std; using ll = long long; using db = double; const float pi = 3.14159265359; #define V vector #define VI V<int> #define P pair<int,int> #define rep(i, a, b, step) for (int i = int(a); i <= int(b); i += step) #define repl(i,a,b,step) for (int i = int(a); i >= int(b); i -= step) #define prime(n) [](ll x) { for (ll i = 2; i * i <= x; ++i) if (x % i == 0) return false; return x > 1; }(n) #define printall(container, ch) for (const auto& elem : container) { std::cout << elem << ch; } std::cout << std::endl; #define lcm(a, b) ((a * b) / gcd(a, b)) #define sn << '\n' #define ed << endl #define sz size() #define print cout << #define debug(x) print #x << " = " << x sn; #define mpII map<int,int> #define mine min_element #define maxe max_element #define all(v) begin(v), end(v) #define txt freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout) #define MEX(a) [](VI a){set<int>elem;for(auto&i:a)elem.insert(i);int ret=0;while(elem.count(ret))ret++;return ret;}(a) #define pb push_back #define pq priority_queue #define rev reverse #define nuyn(a) a.erase(unique(all(a)), end(a)) #define nx next_permutation #define pk pop_back() #define START print "Start" sn #define END print "End" sn #define ff first #define ss second #define ts to_string #define ub upper_bound #define mk make_pair #define lb lower_bound #define testcase int t;cin>>t;while(t--)solution(); const int N = 1e3; int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); int n, m, sum; cin >> n >> m; VI a(n), b(m); V<V<bool>>vis(n, V<bool>(1 << m, 1)); V<VI>graph(N + 1); for (auto& i : a)cin >> i; for (auto& i : b)cin >> i; rep(i, 1, (1 << m) - 1, 1) { sum = 0; rep(j, 0, m - 1, 1) sum += ((i & (1 << j)) > 0) * b[j]; if (sum <= N) graph[sum].pb(i); } auto dfs = [&](auto&& dfs, int mask, int u)->bool { if (u == n - 1)return 1; bool ret = 0; if (!vis[u][mask])return 0; vis[u][mask] = 0; for (auto& i : graph[a[u + 1]]) if (!(mask & i)) ret |= dfs(dfs, mask + i, u + 1); return ret; }; bool ans = 0; for (auto& i : graph[a[0]]) ans |= dfs(dfs, i, 0); print(ans ? "YES" : "NO")sn; }
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