Submission #1122904

#	Time	Username	Problem	Language	Result	Execution time	Memory
1122904		aaaaaarroz	Mosaic (IOI24_mosaic)	C++20	70 / 100	1097 ms	95764 KiB

mosaic

#include "bits/stdc++.h"
#define ll long long
#define pb push_back
#define pii pair<int, int>
using namespace std;
const int N = 4e5+5;
int cnt[N], arcalyk[4][N], tarhun[N][4], par[N];
const int M = 5005;
int dp[M][M];
int wow(int a, int b){
    return (!(a|b)?1:0);
}

vector<ll> mosaic(vector<int> X, vector<int> Y, vector<int> T, vector<int> B, vector<int> L, vector<int> R){
    int n = (int)X.size();
    for (int i = 0; i < n+n; i++)
        cnt[i] = 0;
    map<pii, int> mp;
    for(int i = 1; i <= n; ++i)
        mp[{1, i}] = X[i-1], mp[{i, 1}] = Y[i-1];
    for(int i = 2; i <= n; ++i)
        for(int j = 2; j <= 3; ++j)
            mp[{i, j}] = wow(mp[{i-1, j}], mp[{i, j-1}]);
    for(int i = 2; i <= 3; ++i)
        for(int j = 2; j <= n; ++j)
            mp[{i, j}] = wow(mp[{i-1, j}], mp[{i, j-1}]);

    int i = 3;
    for(int j = 3; j <= n; ++j)
        cnt[i-j+n] = mp[{i, j}];
    int j = 3;
    for(int i = 3; i <= n; ++i)
        cnt[i-j+n] = mp[{i, j}];

    for (int i = 1; i <= 3; i++)
        for (int j = 1; j <= n; j++)
            arcalyk[i][j] = mp[{i,j}] + arcalyk[i][j-1];
    for (int j = 1; j <= 3; j++)
        for (int i = 1; i <= n; i++)
            tarhun[i][j] = mp[{i,j}] + tarhun[i-1][j];
    for (int i = 1; i < n+n; i++)
        par[i] = par[i-1] + cnt[i];

    vector<ll> ans;
    for(int i = 0; i < (int)L.size(); ++i){
        int x = T[i]+1, y = L[i]+1, yy = R[i]+1, xx = B[i]+1;
        ll res = 0;
        while (x <= 3 and x <= xx)
            res += arcalyk[x][yy]-arcalyk[x][y-1], x += 1;
        if (x <= xx){
            while (y <= 3 and y <= yy)
                res += tarhun[xx][y]-tarhun[x-1][y], y += 1;
        }
        if (x <= xx and y <= yy){
            int a = x-y+n, b = x-yy+n, k = xx-x+1;
            swap(a, b);
            int len = b-a+1;
            b += k-1;
            k = min(k, len);
            for (int j = 0; j < k; j++){
                res += cnt[a++] * 1LL * (j+1);
                res += cnt[b--] * 1LL * (j+1);
            }
            if (a > b)
                res -= cnt[++b] * 1LL * k;
            res += (par[b]-par[a-1])*1LL*k;
        }
        ans.pb(res);
    }
    return ans;
}

• Subtask 0: 0 / 0
• Subtask 1: 5 / 5
• Subtask 2: 7 / 7
• Subtask 3: 7 / 7
• Subtask 4: 10 / 10
• Subtask 5: 0 / 8
• Subtask 6: 22 / 22
• Subtask 7: 19 / 19
• Subtask 8: 0 / 22