이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define int long long
const int sz=2e5+5;
const int INF=1e18;
const int MOD=1e9+7;
int arr[sz];
int dp[105][105][1005][5];
void solve()
{
int n,l;
cin>>n>>l;
for(int i=1;i<=n;i++)
cin>>arr[i];
if(n==1)
{
cout<<1;
return;
}
sort(arr+1,arr+n+1);
arr[n+1]=INF;
dp[0][0][0][0]=1;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=i;j++)
{
for(int k=0;k<=l;k++)
{
for(int m=0;m<3;m++)
{
int cost=(2*j-m)*(arr[i+1]-arr[i]);
if(cost>k || (i+j+1-m)>n)
continue;
dp[i][j][k][m]+=dp[i-1][j-1][k-cost][m]+(2*j-m)*dp[i-1][j][k-cost][m];
if(m)
dp[i][j][k][m]+=(3-m)*dp[i-1][j-1][k-cost][m-1];
if(m==1)
dp[i][j][k][m]+=j*(2*dp[i-1][j][k-cost][m-1]+j*dp[i-1][j+1][k-cost][m]);
else if(m==2)
{
if(i==n)
dp[i][j][k][m]+=dp[i-1][j][k-cost][m-1]+dp[i-1][j+1][k-cost][m];
else if(j>1)
dp[i][j][k][m]+=(j-1)*dp[i-1][j][k-cost][m-1];
if(i!=n)
dp[i][j][k][m]+=j*(j-1)*dp[i-1][j+1][k-cost][m];
}
else
dp[i][j][k][m]+=j*(j+1)*dp[i-1][j+1][k-cost][m];
dp[i][j][k][m]%=MOD;
}
}
}
}
int res=0;
for(int i=0;i<=l;i++)
res+=dp[n][1][i][2];
cout<<res%MOD;
}
signed main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int t=1;
//cin>>t;
while(t--)
{
solve();
}
}
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