제출 #1117944

#제출 시각아이디문제언어결과실행 시간메모리
1117944minggaBuilding Bridges (CEOI17_building)C++17
100 / 100
45 ms19224 KiB
#include <bits/stdc++.h> using namespace std; #define ln '\n' #define fi first #define se second #define pb push_back #define all(x) (x).begin(), (x).end() #define sz(x) (int)(x).size() #define int long long const int inf = 2e18; const int N = 1e5 + 7; const int M = 1e6 + 7; int h[N], w[N], n, ps[N], f[N]; struct line { int a, b; line() {} line(int a, int b) : a(a), b(b) {} int calc(int x) { return a * x + b; } int slope() { return a; } }; struct lichao { vector<line> st; lichao() {} int n; lichao(int n) : n(n) { st.resize(n + 1, line(0, inf)); } void update(line f, int l, int r) { if(l > r) return ; int m = (l + r) >> 1; if(l == r) { st[m] = f.calc(l) < st[m].calc(l) ? f : st[m]; return; } if(f.calc(m) < st[m].calc(m)) swap(f, st[m]); if(f.slope() > st[m].slope()) update(f, l, m - 1); if(f.slope() < st[m].slope()) update(f, m + 1, r); } int query(int l, int r, int x) { int m = (l + r) >> 1; int cur = st[m].calc(x); if(x == m) return cur; if(x < m) return min(cur, query(l, m - 1, x)); return min(cur, query(m + 1, r, x)); } }; int a(int i) { return - 2 * h[i]; } int b(int i) { return f[i] - ps[i] + h[i] * h[i]; } signed main() { cin.tie(0) -> sync_with_stdio(0); cin >> n; for(int i = 1; i <= n; i++) cin >> h[i]; for(int i = 1; i <= n; i++) cin >> w[i], ps[i] = ps[i - 1] + w[i]; lichao st(M); st.update(line(a(1), b(1)), 0, M); for(int i = 2; i <= n; i++) { int ext = ps[i - 1] + h[i] * h[i]; f[i] = st.query(0, M, h[i]) + ext; st.update(line(a(i), b(i)), 0, M); } cout << f[n]; }
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