제출 #1117462

#제출 시각아이디문제언어결과실행 시간메모리
1117462thtsshz_bgwrswh여행하는 상인 (APIO17_merchant)C++17
100 / 100
53 ms3428 KiB
#include <bits/stdc++.h> #define FOR(i, x, y) for (int i = x; i < y; i++) typedef long long ll; using namespace std; const ll INF = LLONG_MAX / 2; int n, m, x; ll b[101][1001], s[101][1001]; ll graph[101][101], profit[101][101], graph2[101][101]; void floyd_warshall(ll adj[101][101]) { FOR(i, 1, n + 1) FOR(j, 1, n + 1) FOR(k, 1, n + 1) adj[j][k] = min(adj[j][k], adj[j][i] + adj[i][k]); } int main() { iostream::sync_with_stdio(false); cin.tie(0); cin >> n >> m >> x; FOR(i, 1, n + 1) { FOR(j, 1, n + 1) graph[i][j] = INF; FOR(j, 1, x + 1) cin >> b[i][j] >> s[i][j]; } FOR(i, 0, m) { int u, v, w; cin >> u >> v >> w; graph[u][v] = w; } floyd_warshall(graph); FOR(i, 1, n + 1) FOR(j, 1, n + 1) FOR(k, 1, x + 1) if (s[j][k] != -1 && b[i][k] != -1) profit[i][j] = max(profit[i][j], s[j][k] - b[i][k]); ll l = 1, r = 1e9; while (l <= r) { ll mid = (l + r) / 2; FOR(i, 1, n + 1) FOR(j, 1, n + 1) graph2[i][j] = mid * min(graph[i][j], INF / mid) - profit[i][j]; floyd_warshall(graph2); bool has_nonnegative_cycle = false; FOR(i, 1, n + 1) if (graph2[i][i] <= 0) has_nonnegative_cycle = true; if (has_nonnegative_cycle) l = mid + 1; else r = mid - 1; } cout << r; return 0; }
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