제출 #1116870

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1116870		vjudge1	Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)	C++17	0 / 100	3044 ms	26480 KiB

sortbooks

/**********************************                               //deque,priority_queue
 *    author:  NurkhatKrutoi2009
 *    created: Just now
 *    P.S: tourist ne katai
**********************************/
#include <bits/stdc++.h>
/* for ordered_set <int> st; --> st.order_of_key(j)
#include <ext/pb_ds/assoc_container.hpp> 
#include <ext/pb_ds/tree_policy.hpp> 
using namespace std; 
using namespace __gnu_pbds;  //Delete the other one
template<class T> using ordered_set = tree<T, null_type, 
less<T>, rb_tree_tag, tree_order_statistics_node_update>; 
template<class T> using ordered_multiset = tree<T, null_type, less_equal<T>, 
rb_tree_tag, tree_order_statistics_node_update>;
*//*
#include <algorithm>
#include <iostream>
#include <cmath>
*//*
#pragma GCC optimize("fast-loops")
#pragma comment(linker, "/stack:200000000")
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native,avx2,fma")
#pragma GCC optimization ("unroll-loops")
*/
#define int long long
#define FREOPEN  freopen("  .in", "r", stdin);  freopen("  .out", "w", stdout);
#define sonic ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define FORR( i, x, n, d ) for( int i = x; i >= n; i -= d )
#define FOR( i, x, n, d ) for( int i = x; i <= n; i += d )
#define all(x) (x).begin(), (x).end()
#define pss pair<string,string>
#define nextp next_permutation
#define pii pair<int,int>
#define priq priority_queue
#define mii map<int,int>
#define sz(x) (x).size()
#define stirng string
#define str to_string
#define rev reverse
#define pb push_back
#define ll long long
#define endl '\n'
#define S second
#define F first
const int Pi=3.1415926535;
const int inf=1e10+5;
const int MOD=1e9+7;
const int N=1e5+123;
const int lol=63;
using namespace std;
int tc=1;
void code( ){ 
	int n,m;
	cin>>n>>m;
	int s[n+1];
	FOR(i,1,n,1)cin>>s[i];
	while(m--){
		int l,r,k;
		cin>>l>>r>>k;
		bool ok=1;
		vector <int> v;
		FOR(i,l,r,1)v.pb(s[i]);
		FORR(i,sz(v)-2,1,1)
			if( v[i]<v[i-1] && v[i]+v[i-1]>k){swap( v[i],v[i-1] );ok=0;break;} 
		
		if(ok)cout<<1;
		else cout<<0;
		cout<<'\n';
	}
}signed main(){sonic   //FREOPEN
    //cin>>tc;  
    while(tc--){
    code();
    }
    return 0;
}












 

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