이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define sort undefined_function // To use stable_sort instead sort
#define bpc __builtin_popcount
#define ull unsigned long long
#define ld double
#define ll long long
#define mp make_pair
#define F first
#define S second
# pragma GCC optimize("O2")
//pragma GCC optimize("my solution")
using namespace __gnu_pbds;
using namespace std;
typedef tree<long long, null_type, less_equal<long long>,
rb_tree_tag, tree_order_statistics_node_update> Tree;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll INF = 9223372036854775807LL;
const ll inf = 2147483647;
const ll MOD = 1e9 + 7; //[998244353, 1e9 + 7, 1e9 + 13]
ll gcd(ll a, ll b) {return b ? gcd(b, a % b) : a;}
ll lcm(ll a, ll b) {return a * b / gcd(a, b);}
ll ceil(ll a, ll b) {return (a + b - 1) / b;}
int32_t main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int n;
cin >> n;
vector<pair<ll, ll>> v(n + 1);
for (int i = 1; i <= n; i ++)
cin >> v[i].F >> v[i].S;
stable_sort(v.begin() + 1, v.end());
vector<ll> ta(n + 1);
for (int i = 1; i <= n; i ++)
ta[i] = ta[i - 1] + v[i].S;
//ans = max(ans, ta[j] - v[j].F - ta[i - 1] + v[i].F);
ll ans = 0, mi = -v[1].F;
for (int i = 1; i <= n; i ++) {
ans = max(ans, ta[i] - v[i].F - mi);
mi = min(mi, -ta[i - 1] - v[i].F);
}
cout << ans << "\n";
return 0;
}
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