# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
1116634 | JeffLegendPower | Mobile (BOI12_mobile) | C++17 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// https://oj.uz/problem/view/BOI12_mobile
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define ll long long
#define plli pair<ll, int>
#define pll pair<ll, ll>
#define pii pair<int, int>
// Usage: FOR(i, 0, N) {...}
#define FOR(i, start, end) for(int i = start; i < end; i++)
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int uid(int a, int b) { return uniform_int_distribution<int>(a, b)(rng); }
ll uld(ll a, ll b) { return uniform_int_distribution<ll>(a, b)(rng); }
void setIO(string s) {
freopen((s + ".in").c_str(), "r", stdin);
freopen((s + ".out").c_str(), "w", stdout);
}
struct comp {
bool operator() (const plli& a, const plli& b) const {
return a < b;
}
};
typedef tree<plli, null_type, comp, rb_tree_tag, tree_order_statistics_node_update> ordered_multiset;
// Segtree start
const int Nmax = 1e5; // limit for array size
int N; // array size
int t[2 * Nmax];
int oper(int a, int b) {
return a + b;
}
void build() { // build the tree
for (int i = N - 1; i > 0; --i) t[i] = oper(t[i<<1], t[i<<1|1]);
}
void modify(int p, int value) { // set value at position p
for (t[p += N] = value; p > 1; p >>= 1) t[p>>1] = oper(t[p], t[p^1]);
}
int query(int l, int r) { // on interval [l, r)
int res = 0;
for (l += N, r += N; l < r; l >>= 1, r >>= 1) {
if (l&1) res = oper(res, t[l++]);
if (r&1) res = oper(res, t[--r]);
}
return res;
}
// Segtree end
double dist2(pdd a, pdd b) {
return (a.first - b.first) * (a.first - b.first)
+ (a.second - b.second) * (a.second - b.second);
}
int main() {
// Comment out for interactive problems
ios::sync_with_stdio(false);
cin.tie(nullptr);
int N;
ll L;
cin >> N >> L;
pdd s[N];
for (int i = 0; i < N; i++) cin >> s[i].first >> s[i].second;
double low = 0, high = 1e12;
while (high - low > 0.000001) {
double mid = low + (high - low) / 2;
double x = 0;
for (int i = 0; i < N; i++) {
if (dist2({x, 0}, {s[i]}) > mid*mid) continue;
// let x = s[i].first, y = s[i].second;
// d^2 + y^2 = r^2
// d = sqrt(r^2 - y^2)
// let x2 be the current position
// x2 = x + d
x = s[i].first + sqrt(mid*mid - s[i].second * s[i].second);
}
if (x >= L) high = mid;
else low = mid;
}
cout << fixed << setprecision(10) << high;
}