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답안 #1116602

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1116602 2024-11-22T00:09:23 Z lucascgar Alternating Current (BOI18_alternating) C++17
19 / 100
 88 ms 14076 KB 
#include <bits/stdc++.h>
 
using namespace std;
 
/*
se p dois intervalos [a,b] a cobre b, ent a e b tem que ter tipos diferentes
resposta válida tem que ter alguem que cobre outro
ignorar os cobertos
pensar no círculo
vendo os independentes posso colocar eles de cores diferentes pra aproveitar interseções
parte com eles sozinhos tem que ter intervalos contidos bons
qnt par deles fechou
*/
 
typedef pair<int, int> pii;
typedef pair<long long, long long> pll;
typedef pair<long double, long double> pdd;
 
const int MAXN = 1e5+10;
 
vector<int> f[MAXN][2]; // {start, end} fios
pii cb[MAXN];
bool ty[MAXN];
bool ind[MAXN], iscy[MAXN];  // se é independente, ciclo

int pai[MAXN], qnt[MAXN]; // pros ruins, quem contem ele

signed main(){
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    // cout << fixed << setprecision(7);

    int n, m;
    cin >> n >> m;
 
    int a, b, cyd=0, cyl=1e9+1;

    vector<pair<pii, int>> ord, cy;

    for (int i=0;i<m;i++){
        cin >> a >> b;
        cb[i] = {a,b}, pai[i]=-1;
        if(b<a){
            if (b==a-1){
                a=1,b=n;
                cb[i]={a,b};
            }else{
                cyd = max(cyd, b), cyl = min(cyl, a), iscy[i]=1;
                cy.push_back({{a,-b}, i});
                f[1][0].push_back(i);
                f[b][1].push_back(i);
                f[a][0].push_back(i);
                continue;
            }
        }
        ord.push_back({{a,-b}, i});
        f[a][0].push_back(i);
        f[b][1].push_back(i);
    }
    if (!ord.empty()) sort(ord.begin(), ord.end());
    bool ruim = 0;
    for (auto &x:ord){
        x.first.second = -x.first.second;
        if (x.first.second <= cyd) continue;
        if (x.first.first >= cyl) break;
        cyd = x.first.second, ind[x.second]=1, ruim^=1;
    }

    if (cy.empty() || !ord.empty() && ord[0].first.first == 1 && ord[0].first.second==n) ruim=0;  // se tem um cara que cobre todo mundo ou nn tem ciclos
    else{  // ver ciclos
        sort(cy.begin(), cy.end());
        cyd = 0;
        for (auto &x:cy){
            x.first.second*=-1;
            if (x.first.second<=cyd) continue;
            cyd=x.first.second, ind[x.second]=1, ruim^=1;
        }
    }

    ord.clear();
    cy.clear();

    set<int> all, im;
    vector<int> bn;  // bons (ciclos aparecem só no final)
    int lst=0;

    for (int i=1;i<=n;i++){
        for (auto &u:f[i][0]) if (ind[u]){
            if (!iscy[u] || i>=cyl) bn.push_back(u);
            im.insert(u);
            lst = u;
        }
        while (!f[i][0].empty()){
            int u = f[i][0].back();
            f[i][0].pop_back();
            if (ind[u]) continue;
            all.insert(u);
            pai[u] = lst;  // se um ruim cobre um trecho sem importantes ent ele deveria ser importante
        }

        qnt[i]=all.size()+im.size();
        if (qnt[i]<2){
            cout << "impossible\n";
            return 0;
        }


        while (!f[i][1].empty()){
            int u = f[i][1].back();
            f[i][1].pop_back();
            if (ind[u]) im.erase(u);
            else all.erase(u);
        }
    }
    int sz = bn.size();

    pii want = {-1,-1};

    lst = bn.back();
    for (int i=0;i<sz;lst=bn[i],i++){
        if (i==0 && !iscy[bn.back()]){
            want = {bn[i],lst};
            break;
        }
        int x = bn[i];
        bool vld = 1;
        int l = cb[x].first, r = cb[lst].second;
        // cerr << lst << ' ' << x << ": " << l << '-' << r << '\n';
        if (l<=r){
            for (int j=l;j<=r;j++){
                if (qnt[j]-1 < 2){
                    vld=0;
                    break;
                }
            }
        }else if(iscy[x] && iscy[lst]){
            for (int j=l;j<=n;j++){
                if (qnt[j]-1 < 2){
                    vld=0;
                    break;
                }
            }
            for (int j=1;j<=r;j++){
                if (qnt[j]-1 < 2){
                    vld=0;
                    break;
                }    
            }
        }

        if (vld){
            want = {x, lst};
            break;
        }

    }

    // for (auto &x:bn) cerr << cb[x].first << ' ' << cb[x].second << '\n';

    if (ruim && want.first==-1){  // quantidade é ímpar e não tem uma interseção que é válida nem um cara que cobre todo mundo
        cout << "impossible\n";
        return 0;
    }


    if (!ruim){
        ty[bn[0]]=1;
        for (int i=1;i<sz;i++) ty[bn[i]] = !ty[bn[i-1]];
    }else{
        for (int i=0;i<sz;i++){
            if (bn[i]==want.first) want.first = m+i;
            else if (bn[i]==want.second) want.second=m+i;
        }
        want.first-=m, want.second-=m;
        if (want.second<want.first) swap(want.first, want.second);
        bool color = 1;

        if (want == ((pii){0,sz-1})){
            for (int i=0;i<sz;i++){
                ty[bn[i]] = color, color=!color;
            }
        }else{
            for (int i=want.second;i<sz;i++){
                ty[bn[i]] = color, color=!color;
            }
            for (int i=0;i<=want.first;i++){
                ty[bn[i]] = color, color=!color;
            }
        }

        
    }

    for (int i=0;i<m;i++){
        if (pai[i] == -1) cout << ty[i];
        else cout << !ty[pai[i]];
    }
    cout << '\n';
 
    return 0;
}

Compilation message

alternating.cpp: In function 'int main()':
alternating.cpp:69:63: warning: suggest parentheses around '&&' within '||' [-Wparentheses]
   69 |     if (cy.empty() || !ord.empty() && ord[0].first.first == 1 && ord[0].first.second==n) ruim=0;  // se tem um cara que cobre todo mundo ou nn tem ciclos
      |                       ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
0 / 13.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 4944 KB Output is correct
2 Correct 4 ms 4944 KB Output is correct
3 Correct 3 ms 4944 KB Output is correct
4 Correct 4 ms 5316 KB Output is correct
5 Correct 4 ms 4976 KB Output is correct
6 Correct 4 ms 4944 KB Output is correct
7 Correct 4 ms 4944 KB Output is correct
8 Correct 4 ms 4944 KB Output is correct
9 Correct 4 ms 4944 KB Output is correct
10 Correct 4 ms 4944 KB Output is correct
11 Correct 4 ms 4944 KB Output is correct
12 Incorrect 4 ms 4944 KB no wires in direction 0 between segments 3 and 9
13 Halted 0 ms 0 KB -

Subtask #2
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 4944 KB Output is correct
2 Correct 4 ms 4944 KB Output is correct
3 Correct 3 ms 4944 KB Output is correct
4 Correct 4 ms 5316 KB Output is correct
5 Correct 4 ms 4976 KB Output is correct
6 Correct 4 ms 4944 KB Output is correct
7 Correct 4 ms 4944 KB Output is correct
8 Correct 4 ms 4944 KB Output is correct
9 Correct 4 ms 4944 KB Output is correct
10 Correct 4 ms 4944 KB Output is correct
11 Correct 4 ms 4944 KB Output is correct
12 Incorrect 4 ms 4944 KB no wires in direction 0 between segments 3 and 9
13 Halted 0 ms 0 KB -

Subtask #3
0 / 22.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 4944 KB Output is correct
2 Correct 4 ms 4944 KB Output is correct
3 Correct 3 ms 4944 KB Output is correct
4 Correct 4 ms 5316 KB Output is correct
5 Correct 4 ms 4976 KB Output is correct
6 Correct 4 ms 4944 KB Output is correct
7 Correct 4 ms 4944 KB Output is correct
8 Correct 4 ms 4944 KB Output is correct
9 Correct 4 ms 4944 KB Output is correct
10 Correct 4 ms 4944 KB Output is correct
11 Correct 4 ms 4944 KB Output is correct
12 Incorrect 4 ms 4944 KB no wires in direction 0 between segments 3 and 9
13 Halted 0 ms 0 KB -

Subtask #4
19.0 / 19.0

# 결과 실행 시간 메모리 Grader output
1 Correct 42 ms 13560 KB Output is correct
2 Correct 4 ms 5456 KB Output is correct
3 Correct 16 ms 9480 KB Output is correct
4 Correct 34 ms 12256 KB Output is correct
5 Correct 47 ms 12800 KB Output is correct
6 Correct 41 ms 11772 KB Output is correct
7 Correct 49 ms 13308 KB Output is correct
8 Correct 6 ms 5880 KB Output is correct
9 Correct 4 ms 5456 KB Output is correct
10 Correct 53 ms 14076 KB Output is correct
11 Correct 38 ms 11524 KB Output is correct
12 Correct 46 ms 13200 KB Output is correct
13 Correct 5 ms 5456 KB Output is correct
14 Correct 4 ms 5456 KB Output is correct
15 Correct 53 ms 12028 KB Output is correct
16 Correct 27 ms 12464 KB Output is correct
17 Correct 88 ms 13820 KB Output is correct
18 Correct 80 ms 12028 KB Output is correct
19 Correct 5 ms 5456 KB Output is correct
20 Correct 37 ms 11416 KB Output is correct

Subtask #5
0 / 26.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 4944 KB Output is correct
2 Correct 4 ms 4944 KB Output is correct
3 Correct 3 ms 4944 KB Output is correct
4 Correct 4 ms 5316 KB Output is correct
5 Correct 4 ms 4976 KB Output is correct
6 Correct 4 ms 4944 KB Output is correct
7 Correct 4 ms 4944 KB Output is correct
8 Correct 4 ms 4944 KB Output is correct
9 Correct 4 ms 4944 KB Output is correct
10 Correct 4 ms 4944 KB Output is correct
11 Correct 4 ms 4944 KB Output is correct
12 Incorrect 4 ms 4944 KB no wires in direction 0 between segments 3 and 9
13 Halted 0 ms 0 KB -