이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("Ofast" , "unroll-loops")
#include<bits/stdc++.h>
#define bit(i , j) ((j >> i) & 1)
#define fi first
#define se second
#define all(x) (x).begin() , (x).end()
using namespace std;
const int MAXN = 3e5+100;
const long long inf = 1e9;
const int mod = 1e9+7;
#define int long long
#define pll pair<int , int>
#define MP make_pair
map<int , vector<pll>> Ox , Oy;
int bpow(int a , int b){
if(b == 0) return 1;
int res = bpow(a , b/2);
if(b & 1) return a * res % mod * res % mod;
else return res * res % mod;
}
int32_t main(){
//freopen("seq.inp", "r", stdin);
//freopen("seq.out", "w", stdout);
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int n , m , k; cin >> n >> m >> k;
while(k--){
char c; cin >> c;
if(c == '+') c = 0;
if(c == '-') c = 1;
int x , y; cin >> x >> y;
Ox[x].push_back({y , c});
Oy[y].push_back({x , c});
}
int ans = 0;
int res = bpow(2 , n);
int T = bpow(2 , mod-2);
for(auto x : Ox){
vector<vector<int>> v(2 , vector<int>());
int flag = T;
for(auto y : x.se){
if(v[y.fi%2].size() > 0 && v[y.fi%2].back() != y.se) flag = 0;
v[y.fi%2].push_back(y.se);
}
if(v[0].size() > 0 && v[1].size() > 0 && v[0][0] == v[1][0]) flag = 0;
res = res * flag % mod;
}
ans = res;
res = bpow(2 , m);
vector<pll> d;
int count = 1;
for(auto y : Oy){
vector<vector<int>> v(2 , vector<int>());
int flag = T;
for(auto x : y.se){
if(v[x.fi%2].size() > 0 && v[x.fi%2].back() != x.se) flag = 0;
v[x.fi%2].push_back(x.se);
}
if(v[0].size() > 0 && v[1].size() > 0 && v[0][0] == v[1][0]) flag = 0;
if(flag != 0){
d.push_back({y.fi , y.se[0].se ^ (y.se[0].fi % 2 == 0)});
}else{
count = 0; res = 0; break;
}
res = res * flag % mod;
}
if(count == 0){
cout << (ans + res) % mod << "\n";
return 0;
}
int del = 0;
if(d.size() == 0) del = 2;
else{
vector<vector<int>> v(2 , vector<int>());
del = 1;
for(auto x : d){
if(v[x.fi%2].size() > 0 && v[x.fi%2].back() != x.se) del = 0;
v[x.fi%2].push_back(x.se);
}
if(v[0].size() > 0 && v[1].size() > 0 && v[0][0] == v[1][0]) del = 0;
}
res = (res - del + mod) % mod;
cout << (ans + res) % mod << "\n";
return 0;
}
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