제출 #1115748

#제출 시각아이디문제언어결과실행 시간메모리
1115748jerzyk추월 (IOI23_overtaking)C++17
0 / 100
3 ms764 KiB
#include <bits/stdc++.h> #include "overtaking.h" using namespace std; #define pb push_back #define st first #define nd second typedef long long ll; typedef long double ld; const ll I = 1000'000'000'000'000'000LL; const int II = 2'000'000'000; const ll M = 1000'000'007LL; const int N = 1'007; int n, m, V; ll dis[N], vel[N]; vector<pair<ll, int>> sta[N]; set<pair<ll, pair<ll, ll>>> ran; set<pair<ll, pair<ll, ll>>>::iterator it; vector<pair<pair<ll, ll>, ll>> interv; ll ofs = 0LL; void DoSta() { for(int i = 1; i < m; ++i) { sort(sta[i].begin(), sta[i].end()); ll curma = 0LL, am = 0LL; for(int j = 0; j < n; ++j) { ll na = sta[i][j].st + (dis[i + 1] - dis[i]) * vel[sta[i][j].nd]; na = max(na, curma); sta[i + 1].pb(make_pair(na, sta[i][j].nd)); am = max(na, am); if(j == n - 1 || sta[i][j].st != sta[i][j + 1].st) curma = max(curma, am); //cout << i << " Sta " << sta[i][j].nd << " " << sta[i][j].st << " " << na << "\n"; } } for(int i = 1; i <= m; ++i) { vector<pair<ll, int>> nw; nw.pb(make_pair(-1LL, -1LL)); for(int j = 0; j < n; ++j) { if(vel[sta[i][j].nd] <= V) continue; if(nw.size() == 0 || (nw.back().st != sta[i][j].st)) nw.pb(sta[i][j]); else if(vel[nw.back().nd] < vel[sta[i][j].nd]) nw.back() = sta[i][j]; } sta[i] = nw; } if((int)sta[1].size() == 1) return; for(int i = 1; i < (int)sta[1].size(); ++i) { //cerr << "I: " << sta[1][i].st << "\n"; ran.insert(make_pair(sta[1][i].st, make_pair(sta[1][i].st, sta[1][i].st))); } for(int i = 2; i <= m; ++i) { ll dod = (dis[i] - dis[i - 1]) * V; for(int j = sta[i].size() - 1; j >= 1; --j) { ll x = sta[i][j].st - (dis[i] - dis[i - 1]) * vel[sta[i][j].nd]; ll y = sta[i][j].st - (dis[i] - dis[i - 1]) * V; ll p = I + 10000LL, k = sta[i][j].st - dis[i] * V; it = ran.lower_bound(make_pair(x - ofs, make_pair(-1LL, -1LL))); if(it != ran.end()) p = (*it).nd.nd + 1LL; it = ran.lower_bound(make_pair(x - ofs + 1LL, make_pair(-1LL, -1LL))); while(it != ran.end() && (*it).st + ofs <= y) { p = min(p, (*it).nd.st); ran.erase(*it); it = ran.lower_bound(make_pair(x - ofs + 1LL, make_pair(-1LL, -1LL))); } if(it != ran.end()) k = min(k, (*it).nd.st - 1LL); //cerr << i << " " << j << " " << sta[i][j].st << " " << sta[i][j].nd << " x,y: " << x << " " << y << " p,k: " << p << " " << k << " " << "\n"; if(p <= k) ran.insert(make_pair(sta[i][j].st - ofs - dod, make_pair(p, k))); } //cout << "\n"; ofs += dod; } for(it = ran.begin(); it != ran.end(); ++it) interv.pb(make_pair((*it).nd, (*it).st + ofs)); } void init(int _L, int _N, vector<ll> _T, vector<int> _W, int _X, int _M, vector<int> _S) { n = _N; m = _M; V = _X; for(int i = 1; i <= m; ++i) dis[i] = _S[i - 1]; for(int i = 1; i <= n; ++i) { vel[i] = _W[i - 1]; sta[1].pb(make_pair(_T[i - 1], i)); } DoSta(); } long long arrival_time(ll _Y) { ll tim = _Y; ll ans = tim + dis[m] * V; int p = (upper_bound(interv.begin(), interv.end(), make_pair(make_pair(tim, -1LL), -1LL)) - interv.begin()) - 1; if(interv[p].st.st <= tim && interv[p].st.nd >= tim) ans = interv[p].nd; return ans; }
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