oj.uz

답안 #111531

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
111531 2019-05-15T14:24:08 Z dndhk Building Bridges (CEOI17_building) C++14
30 / 100
 3000 ms 3824 KB 
#include <bits/stdc++.h>

#define pb push_back
#define all(v) ((v).begin(), (v).end())
#define sortv(v) sort(all(v))
#define sz(v) ((int)(v).size())
#define uniqv(v) (v).erase(unique(all(v)), (v).end())
#define umax(a, b) (a)=max((a), (b))
#define umin(a, b) (a)=min((a), (b))
#define FOR(i,a,b) for(int i = (a); i <= (b); i++)
#define rep(i,n) FOR(i,1,n)
#define rep0(i,n) FOR(i,0,(int)(n)-1)
#define FI first
#define SE second
#define INF 2000000000
#define INFLL 1000000000000000000LL


using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

const int MAX_N = 100000;

int N;
vector<pll> vt;
ll DP[MAX_N+1];
ll sum;

int main(){
	scanf("%d", &N);
	for(int i=0; i<N; i++){
		int x;
		scanf("%d", &x);
		vt.pb({x, 0});
	}
	for(int i=0; i<N; i++){
		int y;
		scanf("%d", &y);
		vt[i].second = y;
		sum+=y;
	}
	DP[N-1] = -vt[N-1].second;
	for(int i=N-2; i>=0; i--){
		DP[i] = INFLL;
		for(int j=i+1; j<N; j++){
			DP[i] = min(DP[i], (vt[i].first-vt[j].first)*(vt[i].first-vt[j].first) + DP[j]);
		}
		DP[i] -= vt[i].second;
	}
	cout<<DP[0] + sum;

	return 0;
}

Compilation message

building.cpp: In function 'int main()':
building.cpp:32:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d", &N);
  ~~~~~^~~~~~~~~~
building.cpp:35:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d", &x);
   ~~~~~^~~~~~~~~~
building.cpp:40:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d", &y);
   ~~~~~^~~~~~~~~~

Subtask #1
30.0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 256 KB Output is correct
2 Correct 2 ms 384 KB Output is correct
3 Correct 3 ms 384 KB Output is correct
4 Correct 3 ms 384 KB Output is correct
5 Correct 1 ms 384 KB Output is correct

Subtask #2
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 3062 ms 3824 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #3
0 / 40.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 256 KB Output is correct
2 Correct 2 ms 384 KB Output is correct
3 Correct 3 ms 384 KB Output is correct
4 Correct 3 ms 384 KB Output is correct
5 Correct 1 ms 384 KB Output is correct
6 Execution timed out 3062 ms 3824 KB Time limit exceeded
7 Halted 0 ms 0 KB -