Submission #1115176

#	Time	Username	Problem	Language	Result	Execution time	Memory
1115176		staszic_ojuz	Collecting Stamps 3 (JOI20_ho_t3)	C++17	0 / 100	1 ms	8528 KiB

ho_t3

#include <bits/stdc++.h>
using namespace std;
using ll = long long;

constexpr ll INF = 1e9 + 7;
constexpr int MAXN = 211;
ll dp[MAXN][MAXN][MAXN][2];

int main()
{
    int n, p;
    cin >> n >> p;
    vector<int> r;
    vector<int> l;
    vector<int> t;
    r.push_back(0);
    r.push_back(0);
    l.push_back(0);
    l.push_back(0);
    t.push_back(0);
    for(int i = 0; i < n; ++i)
    {
        int a;
        cin >> a;
        r.push_back(a);
    }
    for(int i = n+1; i >= 2; --i)
        l.push_back(p-r[i]);
    for(int i = 0; i < n; ++i)
    {
        int a;
        cin >> a;
        t.push_back(a);
    }
    t.push_back(0);
    for(int i = 0; i <= n+1; ++i)
    {
        for(int j = 0; j <= n+1; ++j)
        {
            for(int k = 0; k <= n; ++k)
            {
                dp[i][j][k][0] = INF;
                dp[i][j][k][1] = INF;
            }
        }
    }
    dp[1][1][0][0] = 0;
    dp[1][1][0][1] = 0;
    for(int i = 1; i <= n+1; ++i)
    {
        for(int j = 1; j <= n+1; ++j)
        {
            for(int k = 1; k <= n; ++k)
            {
                if(j+i > n+2)
                    break;
                dp[i][j][k][0] = min(dp[i-1][j][k-1][0] + l[i]-l[i-1], dp[i-1][j][k-1][1] + l[i]+r[j]);
                if(dp[i][j][k][0] > t[n-i+2])
                    dp[i][j][k][0] = min(dp[i-1][j][k][0] + l[i]-l[i-1], dp[i-1][j][k][1] + l[i]+r[j]);
                dp[i][j][k][0] = min(dp[i][j][k][0], INF);

                dp[i][j][k][1] = min(dp[i][j-1][k-1][1] + r[j]-r[j-1], dp[i][j-1][k-1][0] + l[i]+r[j]);
                if(dp[i][j][k][1] > t[j-1])
                    dp[i][j][k][1] = min(dp[i][j-1][k][1] + r[j]-r[j-1], dp[i][j-1][k][0] + l[i]+r[j]);
                dp[i][j][k][1] = min(dp[i][j][k][1], INF);
            }
        }
    }
    int odp = 0;
    for(int i = 1; i <= n+1; ++i)
    {
        for(int j = 1; j <= n+1; ++j)
        {
            for(int k = 1; k <= n; ++k)
            {
                for(int zj = 0; zj < 2; ++zj)
                {   
                    if(dp[i][j][k][zj] < INF)
                        odp = max(odp, k);
                }
            }
        }
    }
    cout << odp;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 75