제출 #1115156

#제출 시각아이디문제언어결과실행 시간메모리
1115156elushBitaro, who Leaps through Time (JOI19_timeleap)C++14
4 / 100
3032 ms38604 KiB
#include <bits/stdc++.h> #define x first #define y second #define all(v) v.begin(), v.end() #define chkmax(a, b) a = max(a, b) #define chkmin(a, b) a = min(a, b) using namespace std; typedef long long ll; typedef vector<ll> vi; typedef vector<vi> vvi; typedef pair<ll, ll> pii; typedef vector<pii> vii; const int block = 600; const int MAX_N = 3e5 + 5; pii dpl[MAX_N], dpr[MAX_N]; vii optl[MAX_N], optr[MAX_N]; void Update(int l, int r) { } int Query(int l, int r) { } int l[MAX_N], r[MAX_N], t[MAX_N], a[MAX_N], b[MAX_N], c[MAX_N], d[MAX_N]; int main() { int n, q; cin >> n >> q; for (int i = 1; i < n; i++) cin >> l[i] >> r[i]; for (int i = 0; i < q; i++) { cin >> t[i] >> a[i] >> b[i] >> c[i]; if (t[i] == 2) cin >> d[i]; } for (int i = 0; i < q; i++) { if (t[i] == 1) { l[a[i]] = b[i], r[a[i]] = c[i]; continue; } if (a[i] <= c[i]) { ll ti = b[i], ans = 0; for (int j = a[i]; j < c[i]; j++) { if (ti < l[j]) ti = l[j]; else if (ti >= r[j]) ans += ti - r[j] + 1, ti = r[j] - 1; ti++; } ans += max<ll>(0, ti - d[i]); cout << ans << '\n'; } else { ll ti = b[i], ans = 0; for (int j = a[i] - 1; j >= c[i]; j--) { if (ti < l[j]) ti = l[j]; else if (ti >= r[j]) ans += ti - r[j] + 1, ti = r[j] - 1; ti++; } ans += max<ll>(0, ti - d[i]); cout << ans << '\n'; } } }

컴파일 시 표준 에러 (stderr) 메시지

timeleap.cpp: In function 'int Query(int, int)':
timeleap.cpp:26:1: warning: no return statement in function returning non-void [-Wreturn-type]
   26 | }
      | ^
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