oj.uz

답안 #1113647

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1113647 2024-11-16T22:58:12 Z sunboi 벽 (IOI14_wall) C++17
0 / 100
 3000 ms 43592 KB 
#include <bits/stdc++.h>
using namespace std;


const int N = 2e5 + 1000;
vector<int> a(N);
vector<pair<long long, long long>> t(4 * N);
vector<pair<long long, long long>> lazy(4 * N, {0, -1});

void push(int v, int vl, int vr){
    if (lazy[v].second == -1) return;
    if (lazy[v].second == 1){
            long long x = lazy[v].first;
            t[v * 2] = {min(t[v * 2].first, x), min(t[v * 2].second, x)};
            t[v * 2 + 1] = {min(t[v * 2 + 1].first, x), min(t[v * 2 + 1].second, x)};
            
            if (vl != vr && 2 * v + 1 < 4 *N)push(2 * v, vl, (vl + vr) / 2);
            if (vl != vr && 2 * v + 1 < 4 *N)push(2 * v + 1, (vl + vr) / 2 + 1, vr);
            
            
            
            if (lazy[v * 2].second == 0 || lazy[v * 2 + 1].second == -1) lazy[v * 2] = {x, 1};
            else lazy[v * 2] = {min(lazy[v * 2].first, x), 1};
            
            
            if (lazy[v * 2 + 1].second == 0 || lazy[v * 2 + 1].second == -1) lazy[v * 2 + 1] = {x, 1};
            else lazy[v * 2 + 1] = {min(lazy[v * 2 + 1].first, x), 1};
            
            
            lazy[v] = {0, -1};   
    }else if (lazy[v].second == 0){
           long long x = lazy[v].first;
            t[v * 2] = {max(t[v * 2].first, x), max(t[v * 2].second, x)};
            t[v * 2 + 1] = {max(t[v * 2 + 1].first, x), max(t[v * 2 + 1].second, x)};
            
            
            if (lazy[v * 2].second == 1 || lazy[v * 2 + 1].second == -1) lazy[v * 2] = {x, 0};
            else lazy[v * 2] = {max(lazy[v * 2].first, x), 0};
            
            
            if (lazy[v * 2 + 1].second == 1 || lazy[v * 2 + 1].second == -1) lazy[v * 2 + 1] = {x, 0};
            else lazy[v * 2 + 1] = {max(lazy[v * 2 + 1].first, x), 0};
            
            
            lazy[v] = {0, -1};   
    }
}


void build(int v, int vl, int vr) {
    if (vl == vr) {
        t[v] = {0, 0};
        return;
    }
    int vm = (vl + vr) / 2;
    
    build(2 * v, vl, vm);
    build(2 * v + 1, vm + 1, vr);
    
    t[v] = {max(t[2 * v].first, t[2 * v + 1].first), min(t[2 * v].second, t[2 * v + 1].second)};
}

void update(int v, int vl, int vr, int l, int r, long long x){
    if (vl > r || vr < l) return;
    
    if (vl != vr) push(v, vl ,vr);
    if (vl >= l && vr <= r){
        t[v] = {max(t[v].first, x), max(t[v].second, x)};
        
        if (lazy[v].second == 1 || lazy[v].second == -1) lazy[v] = {x, 0};
        else lazy[v] = {max(lazy[v].first, x), 0};
        
        return;
    }
    int vm = (vl + vr) / 2;
    
    update(2 * v, vl, vm, l, r, x);
    update(2 * v + 1, vm + 1, vr, l, r, x);

    t[v] = {max(t[2 * v].first, t[2 * v + 1].first), min(t[2 * v].second, t[2 * v + 1].second)};
}

void update2(int v, int vl, int vr, int l, int r, long long x){
    if (vl > r || vr < l) return;
    if (vl != vr) push(v, vl ,vr);
    if (vl >= l && vr <= r){
        t[v] = {min(t[v].first, x), min(t[v].second, x)};

        if (lazy[v].second == 0 || lazy[v].second == -1) lazy[v] = {x, 1};
        else lazy[v] = {min(lazy[v].first, x), 1};
        
        return;
    }
    int vm = (vl + vr) / 2;
    
    update2(2 * v, vl, vm, l, r, x);
    update2(2 * v + 1, vm + 1, vr, l, r, x);

    t[v] = {max(t[2 * v].first, t[2 * v + 1].first), min(t[2 * v].second, t[2 * v + 1].second)};
}

int get(int v, int vl, int vr, int x){
    if (vl > x || vr < x) return 0;
    
    if (vr <= x && x <= vl){
        return t[v].first;
    }
    push(v, vl, vr);
    int vm = (vl + vr) / 2;
    
    return max(get(2 * v, vl, vm, x), get(2 * v + 1, vm + 1, vr, x));
    
}

void buildWall(int n, int k, int op[], int left[], int right[], int height[], int finalHeight[]){

    for (int i = 0; i < n; i++){
        a[i] = 0;
    }
    build(1, 0, n - 1);
    for (int i = 0; i < k; i++){
        if (op[i] == 1){
            update(1, 0, n - 1, left[i], right[i], height[i]);
        }else update2(1, 0, n - 1, left[i], right[i], height[i]);
        
        /*for (int j = 0; j < n; j++){
            finalHeight[j] = get(1, 0, n - 1, j);
        }
        
        for (int j = 0; j < n; j++) {
            cout << finalHeight[j] << endl;
        }
        cout << endl;*/
    }
    for (int i = 0; i < n; i++){
        
        finalHeight[i] = get(1, 0, n - 1, i);
    }

    return;
}

Subtask #1
0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 26192 KB Output is correct
2 Correct 6 ms 26448 KB Output is correct
3 Incorrect 6 ms 26192 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #2
0 / 24.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 26192 KB Output is correct
2 Correct 93 ms 34188 KB Output is correct
3 Correct 2338 ms 29712 KB Output is correct
4 Execution timed out 3056 ms 43592 KB Time limit exceeded
5 Halted 0 ms 0 KB -

Subtask #3
0 / 29.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 26192 KB Output is correct
2 Correct 5 ms 26448 KB Output is correct
3 Incorrect 6 ms 26192 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #4
0 / 39.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 26192 KB Output is correct
2 Correct 5 ms 26448 KB Output is correct
3 Incorrect 6 ms 26436 KB Output isn't correct
4 Halted 0 ms 0 KB -