이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = array<int, 2>;
#define all(x) begin(x), end(x)
#define sz(x) (int) (x).size()
template <class Info, class Tag> 
class LazySegtree {
  private:
    const int n;
    vector<Info> t;
    vector<Tag> lz;
       
    void build(int v, int l, int r, const vector<Info> &a) {
        if (l == r) {
            t[v] = a[l];
        } else {
            int m = (l + r) >> 1;
            build(2 * v, l, m, a);
            build(2 * v + 1, m + 1, r, a);
            t[v] = t[2 * v] + t[2 * v + 1];
        }
    }
    void apply(int v, int l, int r, const Tag &x) {
        t[v].apply(x, l, r);
        lz[v].apply(x);
    }
    void pushdown(int v, int l, int r) {
        int m = (l + r) >> 1;
        apply(2 * v, l, m, lz[v]);
        apply(2 * v + 1, m + 1, r, lz[v]);
        lz[v] = Tag();
    }
    void upd(int v, int l, int r, int ql, int qr, const Tag &x) {
        if (qr < l || ql > r) { return; }
        if (ql <= l && r <= qr) {
            apply(v, l, r, x);
        } else {
            pushdown(v, l, r);
            int m = (l + r) >> 1;
            upd(2 * v, l, m, ql, qr, x);
            upd(2 * v + 1, m + 1, r, ql, qr, x);
            t[v] = t[2 * v] + t[2 * v + 1];
        }
    }
    
    Info qry(int v, int l, int r, int ql, int qr) {
        if (qr < l || ql > r) return Info();
        if (l >= ql && r <= qr) return t[v];
        pushdown(v, l, r);
        int m = (l + r) >> 1;
        return qry(2 * v, l, m, ql, qr) + qry(2 * v + 1, m + 1, r, ql, qr);
    }
  public:
    LazySegtree() {}
    
    LazySegtree(int n) : n(n) {
        t.assign(4 << __lg(n), Info());
        lz.assign(4 << __lg(n), Tag());
    }
    LazySegtree(const vector<Info> &a) : n(a.size()) {
        t.assign(4 << __lg(n), Info());
        lz.assign(4 << __lg(n), Tag());
        build(1, 0, n - 1, a);
    }
    /** updates [ql, qr] with the arbitrary update chosen */
    void upd(int ql, int qr, const Tag &x) {
        upd(1, 0, n - 1, ql, qr, x);
    }
    /** @return result of range query on [ql, qr] */
    Info qry(int ql, int qr) {
        return qry(1, 0, n - 1, ql, qr);
    }
};
struct Tag {
    ll add = 0;
    void apply(const Tag &t) {
        add = max(add, t.add);
    }
};
struct Info {
    ll val = 0, best = 0;
    void apply(const Tag &t, int l, int r) {
        best = max(best, val + t.add);
    }
};
/** @return result of joining nodes a and b together */
Info operator+(const Info &a, const Info &b) {
    ll nb = max(a.best, b.best);
    return {max(a.val, b.val), nb};
}
void solve() {
    int n; cin >> n;
    vector<int> a(n);
    for (int &i : a) { cin >> i; }
    vector<vector<pii>> tests(n);
    int q; cin >> q;
    for (int i = 0; i < q; i++) {
        int l, r;
        cin >> l >> r;
        l--, r--;
        tests[l].push_back({r, i});
    }
    vector<Info> arr(n);
    for (int i = 0; i < n; i++) {
        arr[i] = {a[i], a[i]};
    }
    LazySegtree<Info, Tag> st(arr);
    vector<ll> res(q);
    for (int i = n - 1; i >= 0; i--) {
        for (int j = i + 1; j < n; j++) {
            int nxt = j + (j - i);
            if (nxt >= n) { break; }
            st.upd(nxt, n - 1, {a[i] + a[j]});
        }
        for (const auto [r, id] : tests[i]) {
            const auto [val, best] = st.qry(i, r);
            res[id] = best;
        }
    }
    for (int i = 0; i < q; i++) {
        cout << res[i] << "\n";
    }
}
int main() {
    cin.tie(0) -> sync_with_stdio(0);
    int t = 1; // cin >> t;
    while (t--) solve();
}
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