Submission #1113513

#	Time	Username	Problem	Language	Result	Execution time	Memory
1113513		jkb_gryz	Bubble Sort 2 (JOI18_bubblesort2)	C++14	0 / 100	9051 ms	51024 KiB

bubblesort2

#include <bits/stdc++.h>
#include "bubblesort2.h"

using namespace std;
#define ll long long

const int base = 1<<20;
const ll INF = 1e18+7;
const ll MAXN = 1e6+7;

ll tree[base<<1];
set<int> pozycje[MAXN];
ll lazy[base<<1];
int n;

void build(ll v, ll l, ll r){
    if(l == r){
        if(l > n){
            tree[v] = -INF;
            return;
        }
        tree[v] = 0;
    }
    else{
        ll mid = (l + r)/2;
        build(2*v, l, mid);
        build(2*v+1, mid+1, r);

        tree[v] = max(tree[2*v], tree[2*v+1]);
    }
}

void push(ll v){
    lazy[2*v] += lazy[v];
    lazy[2*v+1] += lazy[v];
    
    tree[2*v] += lazy[v];
    tree[2*v+1] += lazy[v];

    lazy[v] = 0;
}

ll p, k;
ll val;

void update(ll v, ll l, ll r){
    if(l > k || r < p) return;
    if(p <= l && r <= k){
        tree[v] += val;
        lazy[v] += val;
    }
    else{
        ll mid = (l+r)/2;

        push(v);

        update(2*v, l, mid);
        update(2*v+1, mid+1, r);

        tree[v] = max(tree[2*v], tree[2*v+1]);
    }
}

ll query(ll v, ll l, ll r){
    if(l > k || r < p) return -INF;
    if(p <= l && r <= k){
        return tree[v];
    }
    else{
        ll mid = (l+r)/2;

        push(v);

        auto lQ = query(2*v, l, mid);
        auto rQ = query(2*v+1, mid+1, r);
        return max(lQ, rQ);
    }
}


vector<int> countScans(vector<int> A, vector<int> X, vector<int> V){
    n = A.size();
	int Q = X.size();
	vector<int> res(Q);

    map<long long, int> skalowanie;
    for(auto i : A){
        skalowanie[i] = 0;
    }
    for(auto i : V){
        skalowanie[i] = 0;
    }
    int id = 0;

    for(auto &i : skalowanie) i.second = ++id, pozycje[i.second].insert(-1);


    build(1, 1, n);
    
    for(int i = 0; i < n; ++i){
        auto vi = A[i];
        p = 0, k = skalowanie[vi]-1;
        val = 1;
        update(1, 1, n);
    }
    
    for(int i = 0; i < Q; ++i){
        p = 0, k = skalowanie[A[X[i]]]-1;
        val = -1;
        update(1, 1, n);

        A[X[i]] = V[i];

        p = 0, k = skalowanie[V[i]]-1;
        val = 1;
        update(1, 1, n);
        
        for(int j = 0; j < n; ++j){
            p = k = skalowanie[A[j]];
            // cerr << query(1, 1, n) << " ";
            res[i] = max((ll)(res[i]), query(1, 1, n) - (n - j - 1));
        }
        // cerr << "\n";
    }

	return res;
}

• Subtask 1: 0 / 17
• Subtask 2: 0 / 21
• Subtask 3: 0 / 22
• Subtask 4: 0 / 40