이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "walk.h"
#include<bits/stdc++.h>
#define pb push_back
#define ff first
#define ss second
#define sz(x) ll(x.size())
#define all(x) x.begin(),x.end()
using namespace std;
typedef long long ll;
typedef pair<ll,ll> ii;
const ll MAX=3e6;
const ll inf=1e18;
vector<ii>gfo[MAX];
ll cur[MAX], dist[MAX];
void dikstra(ll ini){
set<ii> q;
q.insert({0,ini});
dist[ini]=0;
while(sz(q)){
auto x=*q.begin();
q.erase(q.begin());
ll u=x.ss;
ll dist_u=x.ff;
if(dist_u!=dist[u])continue;
for(auto y:gfo[u]){
ll w=y.ss;
ll v=y.ff;
if(dist[v]>dist[u]+w){
dist[v]=dist[u]+w;
q.insert({dist[v], v});
}
}
}
}
map< pair<ll,ll>, ll> M;
set<ll> torre;
long long min_distance(vector<int> x,vector<int> h,
vector<int> l,vector<int> r,
vector<int> y, int s, int g) {
vector<pair<int,ii>> c;
ll m=sz(y);//numero de rascacielos
ll n=sz(x);//numero de torres
for(ll i=0; i<m; i++){
c.pb({y[i],{l[i],r[i]}});// por su altura
}
for(ll i=0; i<n; i++){
torre.insert(i);
}
sort(all(c));
ll nod=0, nod_prev=0, mx=0, pos=0;
for(ll i=0; i<n; i++){
if(!M.count({x[i], 0})){
M[{x[i],0}]=mx+1;
mx++;
cur[i]=0;//altura
}
}
//cout<<mx<<'\n';
vector<ll>ers;
for(auto q:c){//rascacielo en la altura q.ff
ll alt=q.ff;
ll l=q.ss.ff, r=q.ss.ss;
if(!sz(torre))continue;
for(auto it=torre.lower_bound(l); it!=torre.end() && it!=torre.upper_bound(r); it++){
if(alt<=h[*it]){// hay interseccion
if(!M.count({x[*it],alt})){//creamos el nodo
M[{x[*it],alt}]=mx+1;
mx++;
}
nod=M[{x[*it],alt}];
// vertical
gfo[nod].pb({M[{x[*it], cur[*it]}],alt-cur[*it]});
gfo[M[{x[*it], cur[*it]}]].pb({nod,alt-cur[*it]});
cur[*it]=alt;
if(*it==l){
nod_prev=nod;
pos=x[*it];
continue;
}
//horizontal
gfo[nod].pb({nod_prev, x[*it]-pos});
gfo[nod_prev].pb({nod, x[*it]-pos});
nod_prev=nod;
pos=x[*it];
}
else {
ers.pb(*it);
}
}
for(ll w:ers){
torre.erase(torre.find(w));
}
ers.clear();
}
for(ll i=0; i<=mx; i++)dist[i]=inf;
dikstra(M[{x[s],0}]);
ll ans=dist[M[{x[g],0}]];
if(ans==inf)ans=-1;
return ans;
}
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