제출 #1109695

#제출 시각아이디문제언어결과실행 시간메모리
1109695vjudge1Knapsack (NOI18_knapsack)C++17
73 / 100
1062 ms2648 KiB
#include "bits/stdc++.h" #include <type_traits> using namespace std; #pragma GCC optimize("Ofast") #pragma GCC target("avx,avx2,fma") #pragma GCC optimization("unroll-loops") // ============ Macros starts here ============ int recur_depth = 0; #ifdef DEBUG #define dbg(x) {++recur_depth; auto x_=x; --recur_depth; cerr<<string(recur_depth, '\t')<<"\e[91m"<<__func__<<":"<<__LINE__<<"\t"<<#x<<" = "<<x_<<"\e[39m"<<endl;} #else #define dbg(x) #endif // DEBUG template<typename Ostream, typename Cont> typename enable_if<is_same<Ostream, ostream>::value, Ostream&>::type operator<<(Ostream& os, const Cont& v) { os << "["; for (auto& x : v) { os << x << ", "; } return os << "]"; } template<typename Ostream, typename ...Ts> Ostream& operator<<(Ostream& os, const pair<Ts...>& p) { return os << "{" << p.first << ", " << p.second << "}"; } #define readFast \ ios_base::sync_with_stdio(false); \ cin.tie(0); \ cout.tie(0); #ifdef LOCAL #define read() ifstream fin("date.in.txt") #else #define read() readFast #endif // LOCAL // ============ Macros ends here ============ #define fin cin #define ll long long #define sz(x) (int)(x).size() #define all(v) v.begin(), v.end() #define output(x) (((int)(x) && cout << "YES\n") || cout << "NO\n") #define LSB(x) (x & (-x)) #define test cout << "WORKS\n"; const int N = 500 + 15; const int MOD = 1e9 + 7; int n, s; vector<ll> v, k; vector<priority_queue<int, vector<int>, greater<int>>> w_sorted; vector<vector<int>> w; int main() { read(); fin >> s >> n; v.resize(n); w_sorted.resize(s + 1); k.resize(n); for (int i = 0; i < n; ++i) { int weight; fin >> v[i] >> weight >> k[i]; for (int j = 1; j <= k[i] && j * weight <= s; ++j) { w_sorted[weight].push(v[i]); } int left = (s + weight - 1) / weight; while (sz(w_sorted[weight]) > left) { w_sorted[weight].pop(); } } w.resize(s + 1); for (int i = 1; i <= s; ++i) { while (!w_sorted[i].empty()) { w[i].push_back(w_sorted[i].top()); w_sorted[i].pop(); } reverse(all(w[i])); } vector<int> val(s + 1, 0); for (int weight = 1; weight <= s; ++weight) { for (int i = 0; i < w[weight].size(); ++i) { bool changed1 = false; for (int j = s - weight; j >= 0; --j) { if (val[j + weight] < val[j] + w[weight][i]) { val[j + weight] = val[j] + w[weight][i]; changed1 = true; } // val[j + weight] = max(val[j + weight], val[j] + w[weight][i]); } if (!changed1) { break; } } } cout << *max_element(all(val)); return 0; } /*stuff you should look for !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! * test the solution with the given example * int overflow, array bounds, matrix bounds * special cases (n=1?) * do smth instead of nothing and stay organized * WRITE STUFF DOWN * DON'T GET STUCK ON ONE APPROACH ~Benq~*/

컴파일 시 표준 에러 (stderr) 메시지

knapsack.cpp:7: warning: ignoring '#pragma GCC optimization' [-Wunknown-pragmas]
    7 | #pragma GCC optimization("unroll-loops")
      | 
knapsack.cpp: In function 'int main()':
knapsack.cpp:86:27: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   86 |         for (int i = 0; i < w[weight].size(); ++i) {
      |                         ~~^~~~~~~~~~~~~~~~~~
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