제출 #1109282

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1109282		SalihSahin	Financial Report (JOI21_financial)	C++14	5 / 100	216 ms	35824 KiB

Main

#include <bits/stdc++.h>
#define pb push_back
#define int long long
using namespace std;
 
const int mod = 998244353;
const int inf = 1e9 + 20;
const int N = 1e5+5;
 
struct SEGTMX{
    vector<int> tree;
 
    void init(int n){
        tree.assign(4*n, 0);
    }
 
    void update(int ind, int l, int r, int pos, int val){
        if(l == r){
            tree[ind] = val;
        }
        else{
            int m = (l + r)/2;
 
            if(pos <= m) update(ind*2, l, m, pos, val);
            else update(ind*2+1, m+1, r, pos, val);
 
            tree[ind] = max(tree[ind*2], tree[ind*2+1]);
        }
    }
 
    int query(int ind, int l, int r, int ql, int qr){
        if(l > r || l > qr || r < ql) return 0;
        if(l >= ql && r <= qr) return tree[ind];
        else{
            int m = (l + r)/2;
 
            return max(query(ind*2, l, m, ql, qr), query(ind*2+1, m+1, r, ql, qr));
        }
    }
};
 
int32_t main(){
    cin.tie(0); cout.tie(0);
    ios_base::sync_with_stdio(false);
    int n, d;
    cin>>n>>d;
    vector<int> a(n);
    vector<pair<int, int> > b(n);
    for(int i = 0; i < n; i++){
        cin>>a[i];
        b[i] = {a[i], -i};
    }
    sort(b.begin(), b.end());
    SEGTMX seg;
    seg.init(n);
 
    vector<int> nxt(n);
    for(int i = 0; i < n; i++){
        int ind = -b[i].second;
        nxt[ind] = seg.query(1, 1, n, ind + 1, min(n-1, ind + d) + 1);
        nxt[ind] = max(nxt[ind], min(ind + d, n-1));
        seg.update(1, 1, n, ind + 1, nxt[ind]);
    }

    vector<int> prenxt(n);
    prenxt[0] = nxt[0];
    for(int i = 1; i < n; i++){
        prenxt[i] = max(prenxt[i-1], nxt[i]);
    }
    vector<int> lp(n);
    int ind = n-1;
    for(int i = n-1; i >= 0; i--){
        while(ind >= 0 && prenxt[ind] >= i) ind--;
        lp[i] = ind + 1;
    }
 
    SEGTMX segmx;
    segmx.init(n);
    vector<int> dp(n);
    for(int i = 0; i < n; i++){
        int ind = -b[i].second;
        int l = lp[ind] + 1, r = ind + 1;
        int val = segmx.query(1, 1, n, l, r);
        dp[ind] = val + 1;
        segmx.update(1, 1, n, ind + 1, val + 1);
    }
 
    int ans = 0;
    for(int i = 0; i < n; i++){
        ans = max(ans, dp[i]);
    }
    cout<<ans<<endl;
    return 0;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 14
• Subtask 3: 0 / 20
• Subtask 4: 0 / 12
• Subtask 5: 5 / 5
• Subtask 6: 0 / 35