# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
1103116 | agrim_09 | Mutating DNA (IOI21_dna) | C++17 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "dna.h"
#include <bits/stdc++.h>
using namespace std;
// Check for queue, priorioty_queue, stack, ordered_set solutions
// stack => LIFO (whatever goes in last comes out last)
// queue => FIFO (whatever goes in first comes out first)
// priority_queue => Dynamic queries of minimum/maximum
// ordered_set => set in vector form
//[order_of_key(k) gives number of elements less than k, while find_by_order(i) gives i^th element]
// To comment multiple lines : ctrl + /
// To find and replace : ctrl+H
int val(char a, char b){
if(a==b){
return -1;
}
if(a=='1'){
return (b-'2');
}
if(a=='2'){
if(b=='1'){
return 2;
}
return 3;
}
if(a=='3'){
if(b=='1'){
return 4;
}
return 5;
}
return -1;
}
int n; vector<vector<int>>cnt; string s1, s2;
void init(string p, string q){
s1 = p, s2 = q;
n = s1.size(); vector<int>temp(6,0);
for(int i = 0;i<n;i++){
cnt.pb(temp);
}
int tmp = val(s1[0],s2[0]);
if(tmp!=-1){
cnt[0][val(s1[0],s2[0])] = 1;
}
for(int i = 1;i<n;i++){
for(int j = 0;j<6;j++){
cnt[i][j] = cnt[i-1][j];
}
int tmp = val(s1[i],s2[i]);
if(tmp!=-1){
cnt[i][val(s1[i],s2[i])]++;
}
}
}
int get_distance(int l, int r){
int x1 = cnt[r][0], x2 = cnt[r][1], y1 = cnt[r][2], y2 = cnt[r][3];
int z1 = cnt[r][4], z2 = cnt[r][5];
if(l>0){
x1 -= cnt[l-1][0], x2 -= cnt[l-1][1], y1 -= cnt[l-1][2], y2 -= cnt[l-1][3];
z1 -= cnt[l-1][4], z2 -= cnt[l-1][5];
}
int ans = min(x1,y1) + min(x2,z1) + min(y2,z2);
set<int>front; set<int>end;
int r1 = abs(x1-y1), r2 =abs(x2-z1), r3 = abs(y2-z2);
if(x1>y1){
front.insert(1); end.insert(2);
}
if(y1>x1){
front.insert(2); end.insert(1);
}
if(x2>z1){
front.insert(1); end.insert(3);
}
if(z1>x2){
front.insert(3); end.insert(1);
}
if(y2>z2){
front.insert(2); end.insert(3);
}
if(z2>y2){
front.insert(3); end.insert(2);
}
bool yes = (front==end and r1==r2 and r2==r3);
if(yes){
return ans + 2*r1;
}
else{
return -1;
}
}