| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 1101964 | 2024-10-17T08:50:02 Z | AnhPham | 나일강 (IOI24_nile) | C++17 | 0 ms | 0 KB |
#include <bits/stdc++.h>
// #ifdef OP_DEBUG
// #include <algo/debug.h>
// #else
// #define debug(...) 26
// #endif
using namespace std;
// template <class Fun> class y_combinator_result {
// Fun fun_;
// public:
// template <class T> explicit y_combinator_result(T &&fun): fun_(std::forward <T> (fun)) {}
// template <class ...Args> decltype(auto) operator()(Args &&...args) { return fun_(std::ref(*this), std::forward <Args> (args)...); }
// };
// template <class Fun> decltype(auto) y_combinator(Fun &&fun) { return y_combinator_result <std::decay_t <Fun>> (std::forward <Fun> (fun)); }
#define int long long
#define eb emplace_back
#define sz(v) (int)(v).size()
#define all(v) (v).begin(), (v).end()
#define TcT template <class T
// const int MOD = (int)1e9 + 7, INF = (int)4e18 + 18;
// TcT> bool minimize(T &lhs, const T &rhs) { return rhs < lhs ? lhs = rhs, 1 : 0; }
// TcT> bool maximize(T &lhs, const T &rhs) { return rhs > lhs ? lhs = rhs, 1 : 0; }
// void solve();
// int32_t main() {
// cin.tie(nullptr), cout.tie(nullptr) -> sync_with_stdio(false);
// int testcases = 1;
// #define multitest 0
// if (multitest) { cin >> testcases; } for (; testcases--;) { solve(); }
// }
// /* [Pham Hung Anh - 12I - Tran Hung Dao High School for Gifted Student] */
const int mxN = 1e5 + 5;
int dp[mxN];
vector <tuple <int, int, int>> queries;
vector <int> calculate_costs(vector <int> W, vector <int> A, vector <int> B, vector <int> E) {
int N = sz(W), Q = sz(E);
for (int i = 0; i < N; ++i)
queries.eb(W[i], A[i], B[i]);
sort(all(queries));
for (int i = 0; i < N; ++i) {
auto [w, a, b] = queries[i];
W[i] = w, A[i] = a, B[i] = b;
}
vector <int> ans;
for (int q = 0; q < Q; ++q) {
memset(dp, 0, sizeof (dp));
dp[0] = A[0];
for (int i = 1; i < N; ++i) {
dp[i] = dp[i - 1] + A[i];
int sum = 0;
for (int j = i - 1; j >= 0; --j) {
if (W[i] - W[j] <= E[q])
dp[i] = min(dp[i], (j == 0 ? 0 : dp[j - 1]) + B[i] + B[j] + sum);
sum += A[j];
}
}
ans.emplace_back(dp[N - 1]);
}
}