이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define ll long long
#define mp(x, y) make_pair(x, y)
#define sz(v) ((int) (v).size())
#define all(v) (v).begin(), (v).end()
#define MASK(i) (1LL << (i))
#define BIT(x, y) (((x) >> (y)) & 1)
#define pb push_back
#define heap priority_queue
#define max_rng *max_element
#define min_rng *min_element
#define rep(i, n) for(int i = 1, _n = (n); i <= _n; ++i)
#define forn(i, a, b) for(int i = (a), _b = (b); i <= _b; ++i)
#define ford(i, a, b) for(int i = (a), _b = (b); i >= _b; --i)
template <class X, class Y>
inline bool maximize(X &x, Y y) {
return (x < y ? x = y, true : false);
}
template <class X, class Y>
inline bool minimize(X &x, Y y) {
return (x > y ? x = y, true : false);
}
template <class X>
inline void compress(vector<X> &a) {
sort(all(a));
a.resize(unique(all(a)) - a.begin());
}
int ctz(ll x) { return __builtin_ctzll(x); }
int lg(ll x) { return 63 - __builtin_clzll(x); }
int popcnt(ll x) { return __builtin_popcount(x); }
mt19937_64 rng(chrono::high_resolution_clock::now().time_since_epoch().count());
ll rand(ll l, ll r) {
return l + abs((ll) rng()) % (r - l + 1);
}
const ll oo = (ll) 1e18 + 5;
const int inf = (ll) 1e9 + 7, mod = (ll) 1e9 + 7;
const int N = 1e6 + 5, LOG = 30;
void add(int &x, int y) { x += y; if (x >= mod) x -= mod; }
void sub(int &x, int y) { x -= y; if (x < 0) x += mod; }
int n;
int a[N], v[N];
vector<int> cnt[2];
ll calc(ll base) {
int r = n;
ll ans = 0;
forn(l, 1, n) {
while (l < r && v[l] + v[r] > base) r--;
if (v[l] + v[r] <= base)
ans += r - l + 1;
}
return ans;
}
ll ok(int b) {
int val = MASK(b);
ll cur = calc(4 * val - 1) - calc(3 * val - 1)
+ calc(2 * val - 1) - calc(val - 1);
return cur;
}
int main(void) {
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
cin >> n;
rep(i, n) {
cin >> a[i];
}
int all = 0;
int ans = 0;
forn(I, 0, LOG) {
all |= MASK(I);
forn(i, 0, 1) cnt[i].clear();
forn(i, 1, n) {
cnt[BIT(a[i], I)].pb(a[i]);
}
forn(i, 1, sz(cnt[0])) a[i] = cnt[0][i - 1];
forn(i, 1, sz(cnt[1])) a[i + sz(cnt[0])] = cnt[1][i - 1];
forn(i, 1, n) v[i] = a[i] & all;
if (ok(I) & 1) ans += MASK(I);
}
cout << ans;
return 0;
}
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