이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#define ff first
#define ss second
#define inf INT_MAX
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define FAR(i, a, b) for (int i = (a); i >= (b); i--)
#define all(x) (x.begin(), x.end())
const int MOD = 1e9 + 7;
using namespace std;
ll n, m, q;
ll dist(ll a, ll b)
{
return min(abs(a - b), 2 * n - abs(a - b));
}
int main()
{
set<int> best;
cin >> n >> m >> q;
for (ll i = 0; i < m; i++)
{
ll x;
cin >> x;
best.insert(x);
best.insert(x + n);
}
while (q--)
{
ll a, b;
cin >> a >> b;
if (a > b)
swap(a, b);
int l = -1;
int r = -1;
auto it1 = best.upper_bound(a);
if (it1 != best.begin())
{
it1--;
l = (*it1) % (n * 2);
}
else
{
it1 = best.end();
it1--;
l = (*it1) % (n * 2);
}
it1 = best.lower_bound(a);
if (it1 != best.end())
{
r = (*it1) % (n * 2);
}
else
{
it1 = best.begin();
r = (*it1) % (n * 2);
}
ll m1 = dist(a, b);
ll m2 = l == -1 ? 1e9 : dist(a, l) + dist((l + n) % (n * 2), b) + 1;
ll m3 = r == -1 ? 1e9 : dist(a, r) + dist((r + n) % (n * 2), b) + 1;
cout << min(min(m1, m2), m3) << "\n";
}
return 0;
}
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