답안 #1096854

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1096854	2024-10-05T09:31:10 Z	crimson231	Random signals (kriii2_R)	C++17	1 / 4	2631 ms	5584 KB

R

#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <cassert>
#include <vector>
typedef long long ll;
typedef long double ld;
//typedef double ld;
typedef std::vector<int> Vint;
const ld INF = 1e17;
const ld TOL = 1e-7;
const ld PI = acos(-1);
const int LEN = 25;
inline int sign(const ld& x) { return x < -TOL ? -1 : x > TOL; }
inline bool zero(const ld& x) { return !sign(x); }
inline ll sq(ll x) { return x * x; }
inline ld sq(ld x) { return x * x; }
inline ld norm(ld th) {
	while (th < 0) th += 2 * PI;
	while (sign(th - 2 * PI) >= 0) th -= 2 * PI;
	return th;
}

#define START 1
#define CROSS 2
#define END 3

#define HI 0
#define LO 1

int N, M, T, Q;
int I[LEN][LEN][2];
bool IN[LEN][LEN];
ld ANS;
struct Pos {
	ld x, y;
	Pos(ld X = 0, ld Y = 0) : x(X), y(Y) {}
	bool operator == (const Pos& p) const { return zero(x - p.x) && zero(y - p.y); }
	bool operator < (const Pos& p) const { return zero(x - p.x) ? y < p.y : x < p.x; }
	Pos operator + (const Pos& p) const { return { x + p.x, y + p.y }; }
	Pos operator - (const Pos& p) const { return { x - p.x, y - p.y }; }
	Pos operator * (const ld& n) const { return { x * n, y * n }; }
	Pos operator / (const ld& n) const { return { x / n, y / n }; }
	ld operator * (const Pos& p) const { return x * p.x + y * p.y; }
	ld operator / (const Pos& p) const { return x * p.y - y * p.x; }
	Pos rot(ld the) const { return { x * cos(the) - y * sin(the), x * sin(the) + y * cos(the) }; }
	ld Euc() const { return x * x + y * y; }
	ld mag() const { return sqrt(Euc()); }
	ld rad() const { return atan2(y, x); }
}; const Pos O = { 0, 0 };
typedef std::vector<Pos> Polygon;
ld cross(const Pos& d1, const Pos& d2, const Pos& d3, const Pos& d4) { return (d2 - d1) / (d4 - d3); }
Polygon intersection(const Pos& ca, const ld& ra, const Pos& cb, const ld& rb) {
	Pos vec = cb - ca;
	ld distance = vec.mag();
	ld rd = vec.rad();
	if (vec.Euc() > sq(ra + rb) + TOL) return {};
	if (vec.Euc() < sq(ra - rb) - TOL) return {};
	ld X = (ra * ra - rb * rb + vec.Euc()) / (2 * distance * ra);
	if (X < -1) X = -1;
	if (X > 1) X = 1;
	ld h = acos(X);
	Polygon ret;
	ret.push_back(ca + Pos(ra, 0).rot(norm(rd + h)));
	if (zero(h)) return ret;
	ret.push_back(ca + Pos(ra, 0).rot(norm(rd - h)));
	return ret;
}
struct Pii {
	int s, e;
	Pii(int s_ = 0, int e_ = 0) : s(s_), e(e_) {}
};
struct Pow {
	int s, w;
	Pow(int s_, int w_) : s(s_), w(w_) {}
	bool operator < (const Pow& p) const { return s == p.s ? w > p.w : s > p.s; }
};
struct Station {
	int x, y;
	int M, L, U;
	Vint r, s, w;
	Station(int x0 = 0, int y0 = 0, int m0 = 0, int l0 = 0, int u0 = 0) 
		: x(x0), y(y0), M(m0), L(l0), U(u0) { r.clear(); s.clear(); w.clear(); }
	Pos p() const { return Pos(x, y); }
} S[LEN];
struct Event {
	int t;//type
	ld x;
	int ai, aj, ad;
	int bi, bj, bd;
	bool operator < (const Event& e) const {
		if (zero(x - e.x)) {
			return t == e.t ? S[ai].r[aj] > S[e.ai].r[e.aj] : t < e.t;
		}
		return x < e.x;
	}
} E;
std::vector<Event> VE;
struct Signal {
	int i, j, d;
	ld x;
	bool operator < (const Signal& s) const { return i < s.i; }
} SG[LEN * LEN * LEN * LEN];
struct Prob {
	ld p;
	int i, s;
	bool operator < (const Prob& o) const { return s > o.s; }
};
ld prob[LEN];
bool intersection(const int& ai, const int& aj, const int& bi, const int& bj, Polygon& inx) {
	if (S[ai].p() == S[bi].p()) return 0;
	ll x = S[ai].x - S[bi].x;
	ll y = S[ai].y - S[bi].y;
	ll d = x * x + y * y;
	ll ro = S[ai].r[aj] + S[bi].r[bj];
	ll ri = S[ai].r[aj] - S[bi].r[bj];
	if (d >= sq(ro) || d <= sq(ri)) return 0;
	inx = intersection(S[ai].p(), S[ai].r[aj], S[bi].p(), S[ bi].r[bj]);
	assert(inx.size() == 2);
	return 1;
}
ld get_y(const Signal& s, const ld& x) {
	Pos p = S[s.i].p();
	ld r = S[s.i].r[s.j];
	if ((p.x - r) < x && x < (p.x + r)) {
		ld dy = sqrt(r * r - sq(p.x - x));
		return p.y + dy * (s.d == HI ? 1 : -1);
	}
	return p.y;
}
ld green(const Signal& sg, const ld& sx, const ld& ex) {
	ld r = S[sg.i].r[sg.j];
	ld sy = get_y(sg, sx);
	ld ey = get_y(sg, ex);
	int f = sg.d == HI ? 1 : -1;

	Pos c = S[sg.i].p();
	Pos s = Pos(sx, sy);
	Pos e = Pos(ex, ey);

	ld st = norm((s - c).rad());
	ld et = norm((e - c).rad());
	ld t = norm((st - et) * f);
	ld fan = r * r * (t - sin(t)) * .5;
	//ld fan = r * r * (t * .5 - cos(t * .5) * sin(t * .5));

	ld rec = (ex - sx) * (sy + ey) * .5;
	return fan * f + rec;
}
void sweep(const int& k, const ld& x) {
	if (k < 0 || T <= k + 1) return;
	if (zero(SG[k].x - x)) return;
	int sz;

	Signal hi = SG[k + 1];
	Signal lo = SG[k];

	ld ha = green(hi, SG[k].x, x);
	ld la = green(lo, SG[k].x, x);

	ld A = ha - la;
	if (zero(A)) return;

	ld mx = (x + SG[k].x) * .5;
	ld my = (get_y(hi, mx) + get_y(lo, mx)) * .5;
	Pos m = Pos(mx, my);

	for (int i = 0; i < N; i++) {
		Pos v = S[i].p() - m;
		for (int j = 0; j < S[i].M; j++) {
			ll r = S[i].r[j];
			IN[i][j] = sign(r * r - v.Euc()) >= 0;
		}
	}

	std::vector<Prob> P;
	Prob p;
	for (int i = 0; i < N; i++) {
		prob[i] = 1.;
		int all = S[i].U - S[i].L + 1;
		int L = S[i].L;
		int U = S[i].U;
		std::vector<Pow> V;
		for (int j = 0; j < S[i].M; j++) 
			if (IN[i][j]) V.push_back(Pow(S[i].s[j], S[i].w[j]));
		std::sort(V.begin(), V.end());
		sz = V.size();
		for (int j = 0; j < sz; j++) {
			int s = V[j].s;
			int w = V[j].w;
			if (w < L) w = L;
			int diff = U - w + 1;
			if (diff > 0) {
				U = w - 1;
				p.p = (ld)diff / all;
				p.i = i;
				p.s = s;
				P.push_back(p);
			}
		}
	}
	std::sort(P.begin(), P.end());
	ld per = 1.;
	ld total = 0;
	sz = P.size();
	for (int i = 0; i < sz; i++) {
		p = P[i];
		total += p.s * per * p.p / prob[p.i];

		per = per / prob[p.i];
		prob[p.i] -= p.p;
		per = per * prob[p.i];
	}
	SG[k].x = x;
	ANS += total * A;
	return;
}
void sweep_signal(const int& k, const ld& x) {
	sweep(k, x);
	if (0 <= k && k < T) SG[k].x = x;
	return;
}
void solve() {
	T = 0;
	int sz = VE.size();
	for (int i = 0; i < sz; i++) {
		E = VE[i];
		if (E.t == START) {
			int k = 0;
			Signal s;
			for (k = 0; k < T; k++) {
				s = SG[k];
				ld y = get_y(s, E.x);
				if (sign(y - S[E.ai].y) > 0 || (zero(y - S[E.ai].y) && SG[k].d == HI))
					break;
			}

			sweep_signal(k - 1, E.x);
			for (int j = T + 1; j > k + 1; j--) SG[j] = SG[j - 2];
			
			s.i = E.ai;
			s.j = E.aj;
			s.x = E.x;

			s.d = LO; SG[k] = s;
			s.d = HI; SG[k + 1] = s;

			T += 2;
		}
		else if (E.t == END) {
			int ui = I[E.ai][E.aj][HI];
			int di = I[E.ai][E.aj][LO];

			sweep_signal(ui - 1, E.x);
			sweep_signal(ui, E.x);
			sweep_signal(di - 1, E.x);
			sweep_signal(di, E.x);

			int T_ = T;
			T = 0;
			for (int j = 0; j < T_; j++) {
				if (j == ui || j == di) continue;
				SG[T] = SG[j];
				T++;
			}
		}
		else if (E.t == CROSS) {
			int PLUS = -1;
			Vint VI;
			ld nxt = E.x;
			for (int j = i; j < sz; j++) {
				const Event& NE = VE[j];
				if (!zero(E.x - NE.x)) { nxt = NE.x; break; }
				if (NE.t != CROSS) continue;
				PLUS++;
			}

			for (int j = 0; j < T - 1; j++) {
				if (zero(get_y(SG[j], E.x) - get_y(SG[j + 1], E.x))) {
					VI.push_back(j);
					VI.push_back(j + 1);
				}
			}
			std::sort(VI.begin(), VI.end());
			VI.erase(unique(VI.begin(), VI.end()), VI.end());

			int szi = VI.size();
			int ss = -1, ee = -1;
			std::vector<Pii> rev;
			for (int j = 0; j <= szi; j++) {
				int k = -1;
				if (j < szi) {
					k = VI[j];
					sweep_signal(k - 1, E.x);
					sweep_signal(k, E.x);
				}
				if (ss == -1) ss = ee = k;
				else {
					if (k != -1 && zero(get_y(SG[ss], E.x) - get_y(SG[k], E.x))) { ee = k; }
					else {
						if (ss != -1) { rev.push_back(Pii(ss, ee)); }
						ss = ee = k;
					}
				}
			}

			ld mx = (E.x + nxt) * .5;
			int szr = rev.size();
			for (int j = 0; j < szr; j++) {
				int s = rev[j].s;
				int e = rev[j].e;
				std::vector<std::pair<ld, Signal>> VS;
				for (int k = s; k <= e; k++) {
					SG[k].x = E.x;
					VS.push_back(std::make_pair(get_y(SG[k], mx), SG[k]));
				}
				std::sort(VS.begin(), VS.end());
				for (int k = s; k <= e; k++) SG[k] = VS[k - s].second;
			}

			i += PLUS;
		}
		
		for (int j = 0; j < T; j++) {
			const Signal& s = SG[j];
			I[s.i][s.j][s.d] = j;
		}
	}
	return;
}
void init() {
	std::cin.tie(0)->sync_with_stdio(0);
	std::cout.tie(0);
	std::cout << std::fixed;
	std::cout.precision(9);
	ANS = 0;
	std::cin >> N;
	for (int i = 0; i < N; i++) {
		E.ai = i;
		std::cin >> S[i].x >> S[i].y >> S[i].M >> S[i].L >> S[i].U;
		M = S[i].M;
		S[i].r.resize(M);
		S[i].s.resize(M);
		S[i].w.resize(M);
		for (int j = 0; j < M; j++) {
			E.aj = j;
			std::cin >> S[i].r[j] >> S[i].s[j] >> S[i].w[j];

			E.x = S[i].x - S[i].r[j];
			E.t = START;
			VE.push_back(E);

			E.x = S[i].x + S[i].r[j];
			E.t = END;
			VE.push_back(E);

			for (int k = 0; k < i; k++) {
				if (S[i].p() == S[k].p()) continue;
				for (int m = 0; m < S[k].M; m++) {
					Polygon inx;
					if (intersection(i, j, k, m, inx)) {
						for (const Pos& p : inx) {
							E.x = p.x;
							E.t = CROSS;
							VE.push_back(E);
						}
					}
				}
			}
		}
	}
	std::sort(VE.begin(), VE.end());
	return;
}
int main() { init(); solve(); std::cout << ANS << "\n"; return 0; }
//refer to ekzm0204

Subtask #1

1.0 / 1.0

#	결과	실행 시간	메모리	Grader output
1	Correct	0 ms	348 KB	Output is correct
2	Correct	0 ms	348 KB	Output is correct
3	Correct	0 ms	348 KB	Output is correct
4	Correct	0 ms	348 KB	Output is correct
5	Correct	0 ms	348 KB	Output is correct
6	Correct	0 ms	348 KB	Output is correct
7	Correct	1 ms	348 KB	Output is correct
8	Correct	1 ms	348 KB	Output is correct
9	Correct	2 ms	348 KB	Output is correct
10	Correct	1 ms	348 KB	Output is correct
11	Correct	2 ms	348 KB	Output is correct
12	Correct	1 ms	348 KB	Output is correct
13	Correct	0 ms	348 KB	Output is correct
14	Correct	1 ms	344 KB	Output is correct
15	Correct	1 ms	348 KB	Output is correct
16	Correct	1 ms	348 KB	Output is correct
17	Correct	1 ms	348 KB	Output is correct
18	Correct	1 ms	348 KB	Output is correct
19	Correct	1 ms	348 KB	Output is correct
20	Correct	1 ms	348 KB	Output is correct
21	Correct	1 ms	348 KB	Output is correct
22	Correct	1 ms	348 KB	Output is correct
23	Correct	1 ms	348 KB	Output is correct
24	Correct	1 ms	348 KB	Output is correct
25	Correct	1 ms	344 KB	Output is correct
26	Correct	1 ms	348 KB	Output is correct
27	Correct	1 ms	348 KB	Output is correct
28	Correct	1 ms	348 KB	Output is correct
29	Correct	1 ms	348 KB	Output is correct
30	Correct	1 ms	348 KB	Output is correct

Subtask #2

0 / 3.0

#	결과	실행 시간	메모리	Grader output
1	Correct	0 ms	344 KB	Output is correct
2	Correct	7 ms	600 KB	Output is correct
3	Correct	6 ms	604 KB	Output is correct
4	Correct	2631 ms	1004 KB	Output is correct
5	Correct	3 ms	600 KB	Output is correct
6	Correct	54 ms	992 KB	Output is correct
7	Incorrect	525 ms	5584 KB	Output isn't correct
8	Halted	0 ms	0 KB	-