제출 #109645

#	제출 시각UTC-0	아이디	문제	언어	결과	실행 시간	메모리
109645	2019-05-07 08:54:33	futurer	동기화 (JOI13_synchronization)	C++14	100 / 100	2633 ms	93428 KiB

synchronization

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// in the name of ALLAH
#pragma GCC optimize("O3")
#include<bits/stdc++.h>
using namespace std;
#define L(x) (x<<1)
#define R(x) (x<<1|1)
#define MID(l, r) ((l+r)>>1)
#define lb(x) (x&(-x))
#define pii pair<int, int>
#define F first
#define S second
const int N = 1e5+500, M = 2e5+500;
int SZ[N], FRST[N], LST[N], RT[N], DF[M], n, m, q, sz;
vector<pii> adj[N], Yals[N];
vector<int> verts;
bitset<N> B;
struct DS{
    struct node { int mn, mx, lz; } D[M<<3];
    struct undo { int id; node nd; } STK[M*100];
    int stk=0;
    inline void ad(int id) { STK[stk++]={id, D[id]}; }
    inline void merg(int id) { D[id].mx=max(D[L(id)].mx, D[R(id)].mx); D[id].mn=min(D[L(id)].mn, D[R(id)].mn); }
    void build(int id = 1, int l = 0, int r = m+3){
        if(r-l<2) { D[id]={l, l, 0}; return; }
        int mid = MID(l, r);
        build(L(id), l, mid);
        build(R(id), mid, r);
        merg(id);
    }
    void addlst(int s, int e, int id = 1, int l = 0, int r = m+3){
 
 
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컴파일 시 표준 에러 (stderr) 메시지

synchronization.cpp: In function 'int main()':
synchronization.cpp:139:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d %d", &n, &m, &q);
     ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
synchronization.cpp:142:24: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         int a, b; scanf("%d %d", &a, &b);
                   ~~~~~^~~~~~~~~~~~~~~~~
synchronization.cpp:148:21: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         int a; scanf("%d", &a);
                ~~~~~^~~~~~~~~~
synchronization.cpp:156:21: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         int a; scanf("%d", &a);
                ~~~~~^~~~~~~~~~

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 10 / 10
• Subtask 4: 20 / 20
• Subtask 5: 40 / 40