제출 #1093164

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1093164		alexander707070	사이버랜드 (APIO23_cyberland)	C++17	0 / 100	188 ms	183136 KiB

cyberland

#include<bits/stdc++.h>
#define MAXN 5007
using namespace std;

const long double inf=1e15;

struct edge{
    int to,s;
    long double cost;

    inline friend bool operator < (edge fr,edge sc){
        return fr.cost>sc.cost;
    }
};

int n,m,k;
vector<edge> v[MAXN][31];
long double dist[MAXN][31];
long double ans;
bool vis[MAXN][31];
int ability[MAXN];

priority_queue<edge> q;

bool li[MAXN];

bool dfs(int x,int y){
    if(x==y)return true;

    li[x]=true;
    for(edge e:v[x][0]){
        if(li[e.to])continue;
        if(dfs(e.to,y))return true;
    }

    return false;
}

long double gg(long double d,int a,int b){
    if(a>b)return d/2;
    return d;
}

void dijkstra(){

    while(!q.empty()){
        edge curr=q.top();
        q.pop();

        if(vis[curr.to][curr.s])continue;
        vis[curr.s][curr.to]=true;

        for(edge e:v[curr.to][curr.s]){
            if(vis[e.to][e.s] or dist[e.to][e.s]<=gg(dist[curr.to][curr.s]+e.cost,curr.s,e.s))continue;
            dist[e.to][e.s]=gg(dist[curr.to][curr.s]+e.cost,curr.s,e.s);
            q.push({e.to,e.s,dist[e.to][e.s]});
        }
    }

}

double solve(int N, int M, int K, int H, vector<int> X, vector<int> Y, vector<int> C, vector<int> arr){
    n=N; m=M; k=K; H++;

    for(int i=1;i<=m;i++){
        X[i-1]++; Y[i-1]++;
        
        for(int f=0;f<=k;f++){
            v[X[i-1]][f].push_back({Y[i-1],f,C[i-1]});
            v[Y[i-1]][f].push_back({X[i-1],f,C[i-1]});

            if(f>0 and arr[X[i-1]-1]==2)v[X[i-1]][f].push_back({Y[i-1],f-1,C[i-1]});
            if(f>0 and arr[Y[i-1]-1]==2)v[Y[i-1]][f].push_back({X[i-1],f-1,C[i-1]});
        }
    }

    if(!dfs(1,H))return -1;

    for(int i=1;i<=n;i++){
        for(int f=0;f<=k;f++){
            dist[i][f]=inf;
        }
    }

    for(int i=1;i<=n;i++){
        ability[i]=arr[i-1];
        
        if(ability[i]==0 or i==1){
            dist[i][k]=0;
            q.push({i,k,0});
        }
    }

    dijkstra();

    ans=dist[H][0];
    for(int i=0;i<=k;i++){
        ans=min(ans,dist[H][i]);
    }

    return ans;
}

/*int main(){

    cout<<solve(3, 2, 30, 2, {1, 2}, {2, 0}, {12, 4}, {1, 2, 1})<<"\n";
    cout<<solve(4, 4, 30, 3, {0, 0, 1, 2}, {1, 2, 3, 3}, {5, 4, 2, 4}, {1, 0, 2, 1})<<"\n";

    return 0;
}*/

컴파일 시 표준 에러 (stderr) 메시지

cyberland.cpp: In function 'double solve(int, int, int, int, std::vector<int>, std::vector<int>, std::vector<int>, std::vector<int>)':
cyberland.cpp:69:53: warning: narrowing conversion of 'C.std::vector<int>::operator[](((std::vector<int>::size_type)(i - 1)))' from '__gnu_cxx::__alloc_traits<std::allocator<int>, int>::value_type' {aka 'int'} to 'long double' [-Wnarrowing]
   69 |             v[X[i-1]][f].push_back({Y[i-1],f,C[i-1]});
      |                                                     ^
cyberland.cpp:70:53: warning: narrowing conversion of 'C.std::vector<int>::operator[](((std::vector<int>::size_type)(i - 1)))' from '__gnu_cxx::__alloc_traits<std::allocator<int>, int>::value_type' {aka 'int'} to 'long double' [-Wnarrowing]
   70 |             v[Y[i-1]][f].push_back({X[i-1],f,C[i-1]});
      |                                                     ^
cyberland.cpp:72:83: warning: narrowing conversion of 'C.std::vector<int>::operator[](((std::vector<int>::size_type)(i - 1)))' from '__gnu_cxx::__alloc_traits<std::allocator<int>, int>::value_type' {aka 'int'} to 'long double' [-Wnarrowing]
   72 |             if(f>0 and arr[X[i-1]-1]==2)v[X[i-1]][f].push_back({Y[i-1],f-1,C[i-1]});
      |                                                                                   ^
cyberland.cpp:73:83: warning: narrowing conversion of 'C.std::vector<int>::operator[](((std::vector<int>::size_type)(i - 1)))' from '__gnu_cxx::__alloc_traits<std::allocator<int>, int>::value_type' {aka 'int'} to 'long double' [-Wnarrowing]
   73 |             if(f>0 and arr[Y[i-1]-1]==2)v[Y[i-1]][f].push_back({X[i-1],f-1,C[i-1]});
      |                                                                                   ^

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• Subtask 8: 0 / 3