제출 #1091365

#제출 시각아이디문제언어결과실행 시간메모리
1091365guymmkBouquet (EGOI24_bouquet)C++14
8 / 100
20 ms8024 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <random> using namespace std; using namespace __gnu_pbds; #pragma GCC optimize("O3,Ofast,unroll-loops") //#pragma GCC target("popcnt") //#define int long long #define ll long long #define ld long double #define endl '\n' #define pii pair<int,int> #define debug(...) printf(__VA_ARGS__) //#define debug(...) #define trace(x) cout<<#x<<"="<<x<<endl; //#define trace(x) #define vi vector<int> #define popcnt(x) (int)__builtin_popcount(x) #define vpii vector<pii > #define vvi vector<vector<int> > #define umap unordered_map #define uset unordered_set #define mk make_pair #define pb push_back #define pob pop_back #define _ <<' '<< #define all(x) x.begin(),x.end() #define allr(x) x.rbegin(),x.rend() #define read(x) for (auto& zu: (x)) cin >> zu; #define write(x) for (auto& zu: (x))cout << zu<<' '; cout<<endl; static inline void print(const int &x) { if (x > 9)print(x / 10); putchar('0' + x % 10); } #define F first #define S second template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; template<class T> using ordered_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>; #define mustawa ios::sync_with_stdio(false);cin.tie(nullptr); #define mishari main const int inf=1e9+7; void fa(bool ok){ cout << (ok ? "YES": "NO") << endl;} int pw(ll a, ll b, ll mod= 1e9 + 7){ ll result = 1; while(b) { if(b&1) { result = (result*a)%mod; } a = (a * a) % mod; b>>=1; } return result; } inline void usaco(string s) { freopen((s + ".in").c_str(), "r", stdin); freopen((s + ".out").c_str(), "w", stdout); }int gcd(int a,int b){ if (b == 0)return a; return gcd(b, a % b); } int lcm(int a, int b){ return (a / gcd(a, b)) * b; } //long double log(int base,int x){ // return log2(x)/log(base); //} int log(int base,int x){ return (int)(log2(x)/log(base)); } void vod(){} int sum(int l,int r){ if(l>r)swap(l,r); int a=((l-1)*(l))/2; int b=(r*(r+1))/2; return b-a; } int L[(int)2e5+5],R[(int)(2e5+5)],dp[(int)2e5+5],n; int r0(int i){ if(i<0)return 0; if(dp[i]!=-1)return dp[i]; return dp[i]=max(r0(i-1),r0(i-L[i]-1)); } void solve(){ cin>>n; bool b=0; for(int i=0;i<n;i++){ cin>>L[i]>>R[i]; if(L[i]!=R[i])b=1; if(i&&L[i]!=L[i-1])b=1; }if(n<=1000){ for(int i=0;i<n;i++){ dp[i]=1; for(int j=0;j<i-L[i];j++){ if(j+R[i]<i)dp[i]=max(dp[i],dp[j]+1); } }return cout<<dp[n-1]<<endl,vod(); } if(!b)return cout<<(n-1)/(L[0]+1)+1<<endl,vod(); else { memset(dp,-1,sizeof dp); cout<<r0(n-1)<<endl; } } signed mishari() { mustawa; //usaco("nocross"); int tescases = 1; //cin>>tescases; for (int i = 1; i <= tescases; i++) { //cout<<"Case "<<i<<":"<<endl; solve(); } }
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