이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define x first
#define y second
struct Edge{
ll v, a, b;
};
vector<Edge> T[200005], C[200005];
ll N, Q, Sum = 0, Ans[200005], Val[200005];
void cal1(ll u, ll p){
for(auto e : T[u]){
if(e.v == p) continue;
Val[1] += e.b;
cal1(e.v, u);
}
}
void cal2(ll u, ll p){
for(auto e : T[u]){
if(e.v == p) continue;
Val[e.v] = Val[u] - e.b + e.a;
cal2(e.v, u);
}
}
ll mxD = 0, U = 1;
void Dia(ll u, ll p, ll d){
if(mxD < d + Val[u]){
mxD = d + Val[u], U = u;
}
for(auto e : T[u]){
if(e.v == p) continue;
Dia(e.v, u, d + e.a + e.b);
}
}
int main(){
cin.tie(0) -> sync_with_stdio(0);
cin >> N;
for(ll i = 1; i < N; i++){
ll u, v, a, b; cin >> u >> v >> a >> b;
T[u].push_back({v, a, b}); T[v].push_back({u, b, a});
Sum += a + b;
}
cal1(1, -1); cal2(1, -1);
Ans[1] = Sum - *max_element(Val + 1, Val + N + 1);
Dia(1, -1, 0);
ll V = U;
Dia(V, -1, 0);
Ans[2] = Sum - (mxD + Val[V]) / 2;
cin >> Q;
while(Q--){
ll t; cin >> t;
cout << Ans[t] << '\n';
}
}
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