oj.uz

답안 #1091038

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1091038 2024-09-19T15:05:47 Z underwaterkillerwhale Tourism (JOI23_tourism) C++17
0 / 100
 5000 ms 47184 KB 
#include <bits/stdc++.h>
#define ll              long long
#define pii             pair<int,int>
#define pll             pair<ll,ll>
#define rep(i,m,n)      for(int i=(m); i<=(n); i++)
#define reb(i,m,n)      for(int i=(m); i>=(n); i--)
#define iter(id, v)     for(auto id : v)
#define fs              first
#define se              second
#define MP              make_pair
#define pb              push_back
#define bit(msk, i)     ((msk >> i) & 1)
#define SZ(v)           (ll)v.size()
#define ALL(v)          v.begin(),v.end()

using namespace std;

mt19937_64 rd(chrono :: steady_clock :: now ().time_since_epoch().count());
ll Rand (ll l, ll r) { return uniform_int_distribution<ll> (l, r) (rd); }

const int N = 1e5 + 7;
const int Mod = 1e9 + 2022; ///loonf mod sai
const int INF = 1e9;
const ll BASE = 137;
const int szBL = 320;

struct Query {
    int fs, se, id;
};

int n, m, Q;
vector<int> ke[N];
Query qr[N];
int C[N];

int high[N], szC[N], euler[2 * N], posin[N], pa[N], ein[N], eout[N];
pii flca[2 * N][25];

void pdfs (int u, int p) {
    static int sz = 0, time_dfs = 0;
    high[u] = high[p] + 1;
    pa[u] = p;
    szC[u] = 1;

    flca[++sz][0] = MP(high[u], u);
    posin[u] = sz;
    ein[u] = ++time_dfs;
    iter (&v, ke[u]) {
        if (v != p) {
            pdfs(v, u);
            szC[u] += szC[v];
            flca[++sz][0] = MP(high[u], u);
        }
    }
    eout[u] = time_dfs;
}

void init_LCA () {
    for (int j = 1; (1 << j) <= 2 * n; ++j)
        for (int i = 1; i + (1 << j) - 1 <= 2 * n; ++i)
            flca[i][j] = min(flca[i][j - 1], flca[i + (1 << j - 1)][j - 1]);
}

int LCA (int u, int v) {
    u = posin[u];
    v = posin[v];
    if (u > v) swap(u, v);
    int K = 31 - __builtin_clz(v - u + 1);
    return min(flca[u][K], flca[v - (1 << K) + 1][K]).se;
}

namespace sub2 {

    int pre[N];

    void dfs (int u, int p, int &res) {
        iter (&v, ke[u]) {
            if (v != p) {
                dfs(v, u, res);
                pre[u] += pre[v];
            }
        }
        if (pre[u] > 0) ++res;
    }

    void solution () {
        rep (q, 1, Q) {
            rep (i, 1, n) pre[i] = 0;
            int L = qr[q].fs, R = qr[q].se;
            int Lca = C[L];
            rep (i, L, R) {
                Lca = LCA(Lca, C[i]);
            }
            rep (i, L, R) {
                pre[C[i]]++;
                pre[pa[Lca]]--;
            }
            int res = 0;
            dfs(1, 0, res);
            cout << res <<"\n";
        }

    }

}

namespace sub6 {

    int sptLCA[N][25];
    ll res = 0;
    int ptrL = 1, ptrR = 0;

    multiset<pii> S;

    void update (int u, int val) {
        pii cur = MP(ein[u], u);
        if (val == -1) {
            assert(S.find(cur) != S.end());
            S.erase(S.find(cur));
        }
        int lc = -1, rc = -1;
        auto it = S.lower_bound(cur);
        if (it != S.end())  rc = it->se;
        if (it != S.begin()) lc = prev(it)->se;
        if (rc == -1 && lc == -1) res += val * high[u];
        else {
            if (rc != -1 && ein[rc] <= eout[u]) {}
            else if (lc != -1 && eout[lc] >= ein[u]) {
                if (rc == -1) res += val * (high[u] - high[lc]);
                else {
                    int nearest = LCA(u, rc);
                    if (high[nearest] < high[lc]) nearest = lc;
                    res += val * (high[u] - high[nearest]);
                }
            }
            else {
                if (rc == -1) rc = u;
                if (lc == -1) lc = u;
                int nearest = LCA(rc, lc);
                res += val * (high[u] - high[nearest]);
            }
//                cout << u <<" "<<lc <<","<<rc<<" "<<res<<","<<val<<"\n";
        }

        if (val == 1) S.insert(cur);
//        cout << ptrL <<" "<<ptrR<<" "<<val<<":\n";
//        iter (&id, S) cout << id.se<<" ";
//        cout<<"\n";
    }

    void shifting (int L, int R) {
        while (ptrL > L) {
            --ptrL;
            update(C[ptrL], 1);
        }
        while (ptrR < R) {
            ++ptrR;
            update (C[ptrR], 1);
        }
        while (ptrL < L) {
            update(C[ptrL], -1);
            ++ptrL;
        }
        while (ptrR > R) {
           update (C[ptrR], -1);
           --ptrR;
        }
    }

    void solution () {
        sort (qr + 1, qr + 1 + Q, [] (Query A, Query B) {
            if (A.fs / szBL != B.fs / szBL) return A.fs < B.fs;
            else if (!((A.fs / szBL) &1)) return A.se < B.se;
            else return A.se > B.se;
        });
        rep (i, 1, m) sptLCA[i][0] = C[i];

        for (int j = 1; (1 << j) <= m; ++j)
        for (int i = 1; i + (1 << j) - 1 <= m; ++i)
            sptLCA[i][j] = LCA(sptLCA[i][j - 1], sptLCA[i + (1 << j - 1)][j - 1]);

        auto get_LCA = [] (int L, int R) {
            int K = 31 - __builtin_clz(R - L + 1);
            return LCA(sptLCA[L][K], sptLCA[R - (1 << K) + 1][K]);
        };

        vector<int> Ans(Q + 1);
        rep (q, 1, Q) {
            int L = qr[q].fs, R = qr[q].se, id = qr[q].id;
            shifting(L, R);
            Ans[id] = res - high[get_LCA(L, R)] + 1;
//            cout << id<<":"<<Ans[id] <<","<<get_LCA(L, R)<<"\n";
        }
        rep (i, 1, Q) cout << Ans[i] <<"\n";
    }
}


void solution() {
    cin >> n >> m >> Q;
    rep (i, 1, n - 1) {
        int u, v;
        cin >> u >> v;
        ke[u].pb(v);
        ke[v].pb(u);
    }
    rep (i, 1, m) cin >> C[i];
    rep (i, 1, Q) cin >> qr[i].fs >> qr[i].se, qr[i].id = i;
    pdfs(1, 0);
    init_LCA();
//    if (n <= 2000 && m <= 2000 && Q <= 2000) sub2 :: solution();
//    else
        sub6 :: solution();

}

#define file(name) freopen(name".inp","r",stdin); \
freopen(name".out","w",stdout);
int main () {
//    file("c");
//    ios_base :: sync_with_stdio(false); cin.tie(0); cout.tie(0);
    int num_Test = 1;
//    cin >> num_Test;
    while (num_Test--)
        solution();
}
/*
no bug +8
chu y break hay return se lam hong logic
xet transition cua i va i + 1
construct ket qua
chu y truong hop : KHONG CO GI

ko làm được

hướng 1: đổi hướng làm
hướng 2: đưa ra nhận xét

tim mo hinh bai toan sau khi doc de

trung ten bien trong ham gan nhat co the dan den sai

10 7 3
6 5
3 6
9 3
8 3
7 8
7 1
2 5
7 10
8 4
9 4 10 1 10 7 6
4 4
1 3
6 7



*/

Compilation message

tourism.cpp: In function 'void init_LCA()':
tourism.cpp:61:63: warning: suggest parentheses around '-' inside '<<' [-Wparentheses]
   61 |             flca[i][j] = min(flca[i][j - 1], flca[i + (1 << j - 1)][j - 1]);
      |                                                             ~~^~~
tourism.cpp: In function 'void sub6::solution()':
tourism.cpp:180:69: warning: suggest parentheses around '-' inside '<<' [-Wparentheses]
  180 |             sptLCA[i][j] = LCA(sptLCA[i][j - 1], sptLCA[i + (1 << j - 1)][j - 1]);
      |                                                                   ~~^~~

Subtask #1
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2652 KB Output is correct
2 Correct 1 ms 2796 KB Output is correct
3 Correct 1 ms 2652 KB Output is correct
4 Incorrect 3 ms 2964 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #2
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2652 KB Output is correct
2 Correct 1 ms 2796 KB Output is correct
3 Correct 1 ms 2652 KB Output is correct
4 Incorrect 3 ms 2964 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #3
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2652 KB Output is correct
2 Correct 2 ms 2792 KB Output is correct
3 Correct 13 ms 3164 KB Output is correct
4 Execution timed out 5062 ms 47184 KB Time limit exceeded
5 Halted 0 ms 0 KB -

Subtask #4
0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2648 KB Output is correct
2 Incorrect 100 ms 33872 KB Output isn't correct
3 Halted 0 ms 0 KB -

Subtask #5
0 / 24.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 2648 KB Output is correct
2 Correct 3 ms 2896 KB Output is correct
3 Correct 13 ms 3164 KB Output is correct
4 Execution timed out 5058 ms 44776 KB Time limit exceeded
5 Halted 0 ms 0 KB -

Subtask #6
0 / 41.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 2652 KB Output is correct
2 Correct 1 ms 2796 KB Output is correct
3 Correct 1 ms 2652 KB Output is correct
4 Incorrect 3 ms 2964 KB Output isn't correct
5 Halted 0 ms 0 KB -