제출 #1088776

#제출 시각아이디문제언어결과실행 시간메모리
1088776TrinhKhanhDungThe Kingdom of JOIOI (JOI17_joioi)C++14
100 / 100
2082 ms118092 KiB
#include <bits/stdc++.h>
#define ll long long
#define fi first
#define se second
#define sz(x) (int)x.size()
#define ALL(v) v.begin(),v.end()
#define MASK(k) (1LL << (k))
#define BIT(x, i) (((x) >> (i)) & 1)
#define oo (ll)1e18
#define INF (ll)1e9
#define MOD (ll)(1e9 + 7)

using namespace std;

template<class T1, class T2>
    bool maximize(T1 &a, T2 b){if(a < b){a = b; return true;} return false;}

template<class T1, class T2>
    bool minimize(T1 &a, T2 b){if(a > b){a = b; return true;} return false;}

template<class T1, class T2>
    void add(T1 &a, T2 b){a += b; if(a >= MOD) a -= MOD;}

template<class T1, class T2>
    void sub(T1 &a, T2 b){a -= b; if(a < 0) a += MOD;}

template<class T>
    void cps(T &v){sort(ALL(v)); v.resize(unique(ALL(v)) - v.begin());}

const int MAX = 2e3 + 10;

int N, M;
int a[MAX][MAX], b[MAX][MAX], c[MAX][MAX], d[MAX][MAX], ma, mi = INF;

bool OK(int k, int a[MAX][MAX]){
    vector<vector<int>> val(N + 3, vector<int>(M + 3, 0));
    for(int i = 1; i <= N; i++){
        for(int j = 1; j <= M; j++){
            if(a[i][j] - mi <= k) val[i][j] += 1;
            if(ma - a[i][j] <= k) val[i][j] += 2;
            if(val[i][j] == 0) return false;
        }
    }
    int cur = M, t = 0;
    for(int i = 1; i <= N; i++){
        for(int j = 1; j <= cur; j++){
            if(val[i][j] == 3 || val[i][j] == t) continue;
            if(t == 0) t = val[i][j];
            else{
                cur = j - 1;
                break;
            }
        }
        for(int j = cur + 1; j <= M; j++){
            if(val[i][j] != 3 && val[i][j] == t) return false;
        }
    }
    return true;
}

void solve(){
    cin >> N >> M;
    for(int i = 1; i <= N; i++){
        for(int j = 1; j <= M; j++){
            cin >> a[i][j];
            maximize(ma, a[i][j]);
            minimize(mi, a[i][j]);
        }
    }
    for(int i = 1; i <= N; i++){
        for(int j = 1; j <= M; j++){
            b[i][j] = a[i][M + 1 - j];
            c[i][j] = a[N + 1 - i][j];
            d[i][j] = a[N + 1 - i][M + 1 - j];
        }
    }
    int l = 0, r = ma - mi;
    while(l < r){
        int m = (l + r) >> 1;
        if(OK(m, a) || OK(m, b) || OK(m, c) || OK(m, d)){
            r = m;
        }
        else{
            l = m + 1;
        }
    }
    cout << r << '\n';
}

int main(){
    ios_base::sync_with_stdio(0); cin.tie(0);
    // freopen("order.inp","r",stdin);
    // freopen("order.out","w",stdout);

    solve();

    return 0;
}
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