This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <iostream>
#include <stdio.h>
#include <math.h>
#include <string.h>
#include <time.h>
#include <stdlib.h>
#include <string>
#include <bitset>
#include <vector>
#include <set>
#include <map>
#include <queue>
#include <algorithm>
#include <sstream>
#include <stack>
#include <iomanip>
#include <assert.h>
using namespace std;
#define pb push_back
#define mp make_pair
typedef pair<int,int> pii;
typedef long long ll;
typedef double ld;
typedef vector<int> vi;
#define fi first
#define se second
#define fe first
#define FO(x) {freopen(#x".in","r",stdin);freopen(#x".out","w",stdout);}
#define Edg int M=0,fst[SZ],vb[SZ],nxt[SZ];void ad_de(int a,int b){++M;nxt[M]=fst[a];fst[a]=M;vb[M]=b;}void adde(int a,int b){ad_de(a,b);ad_de(b,a);}
#define Edgc int M=0,fst[SZ],vb[SZ],nxt[SZ],vc[SZ];void ad_de(int a,int b,int c){++M;nxt[M]=fst[a];fst[a]=M;vb[M]=b;vc[M]=c;}void adde(int a,int b,int c){ad_de(a,b,c);ad_de(b,a,c);}
#define es(x,e) (int e=fst[x];e;e=nxt[e])
#define esb(x,e,b) (int e=fst[x],b=vb[e];e;e=nxt[e],b=vb[e])
#define SZ 666666
int n; ld a[SZ],b[SZ],sa[SZ],sb[SZ];
bool ok(ld x)
{
int l=0,r=0;
while(1)
{
if(sa[l]-l-r<x)
{
if(l==n) return 0; ++l;
}
else if(sb[r]-l-r<x)
{
if(r==n) return 0; ++r;
}
else break;
}
return 1;
}
int main()
{
cin>>n;
for(int i=1;i<=n;++i)
cin>>a[i]>>b[i];
sort(a+1,a+1+n,greater<ld>());
sort(b+1,b+1+n,greater<ld>());
for(int i=1;i<=n;++i)
sa[i]=sa[i-1]+a[i],
sb[i]=sb[i-1]+b[i];
ld l=0,r=1e9;
for(int i=1;i<=150;++i)
{
ld m=(l+r)/2;
if(ok(m)) l=m; else r=m;
}
printf("%.4lf\n",(double)l);
}
Compilation message (stderr)
sure.cpp: In function 'bool ok(ld)':
sure.cpp:42:4: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
if(l==n) return 0; ++l;
^~
sure.cpp:42:23: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
if(l==n) return 0; ++l;
^~
sure.cpp:46:4: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
if(r==n) return 0; ++r;
^~
sure.cpp:46:23: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
if(r==n) return 0; ++r;
^~
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