This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("Ofast")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
typedef long long ll;
#define int ll
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define pb push_back
#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
#define mispertion ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0)
#define F first
#define S second
#define getlast(s) (*s.rbegin())
#define debg cout << "OK\n"
const ld PI = 3.1415926535;
const int N = 5e5 + 10;
const int M = 1e5 + 10;
int mod = 1e9+7;
const int infi = INT_MAX;
const ll infl = 2e18;
const int P = 505319;
const ld eps = 1e-9;
int mult(int a, int b){
return a * 1LL * b % mod;
}
int sum(int a, int b){
a %= mod;
b %= mod;
if(a + b >= mod)
return a + b - mod;
if(a + b < 0)
return a + b + mod;
return a + b;
}
int binpow(int a, int n){
if (n == 0)
return 1;
if (n % 2 == 1){
return mult(binpow(a, n - 1), a);
}
else{
auto b = binpow(a, n / 2);
return mult(b, b);
}
}
int n, m, h[N], l[N], r[N];
vector<pii> g[N];
void dfs(int v, int w){
if(v > n){
h[v] = 0;
l[v] = w;
r[v] = w;
return;
}
multiset<int> lm, rm;
for(auto ee : g[v]){
int u = ee.F, w = ee.S;
dfs(u, w);
h[v] += h[u];
if(sz(lm) == 0){
lm.insert(l[u]);
rm.insert(r[u]);
}else{
int cl = *lm.rbegin();
int cr = *rm.begin();
if(cr < l[u])
h[v] += l[u] - cr;
else if(r[u] < cl)
h[v] += (cl - r[u]);
if(l[u] <= cl)
lm.insert(l[u]);
else
rm.insert(l[u]);
if(r[u] <= cl)
lm.insert(l[u]);
else
rm.insert(r[u]);
if(sz(lm) > sz(rm)){
int x = *lm.rbegin();
lm.erase(lm.find(x));
rm.insert(x);
}else if(sz(lm) < sz(rm)){
int x = *rm.begin();
rm.erase(rm.begin());
lm.insert(x);
}
}
}
assert(sz(lm) == sz(rm));
l[v] = *lm.rbegin();
r[v] = *rm.begin();
l[v] += w;
r[v] += w;
}
void solve(){
cin >> n >> m;
for(int i = 2; i <= n + m; i++){
int p, w;
cin >> p >> w;
g[p].pb({i, w});
}
dfs(1, 0);
cout << h[1] << '\n';
}
signed main(){
mispertion;
int t = 1;
//cin >> t;
while (t--){
solve();
}
return 0;
}
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