Submission #1087324

#TimeUsernameProblemLanguageResultExecution timeMemory
1087324steveonalexKitchen (BOI19_kitchen)C++17
0 / 100
37 ms860 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef unsigned long long ull; #define MASK(i) (1LL << (i)) #define GETBIT(mask, i) (((mask) >> (i)) & 1) #define ALL(v) (v).begin(), (v).end() #define block_of_code if(true) ll max(ll a, ll b){return (a > b) ? a : b;} ll min(ll a, ll b){return (a < b) ? a : b;} ll gcd(ll a, ll b){return __gcd(a, b);} ll lcm(ll a, ll b){return a / gcd(a, b) * b;} ll LASTBIT(ll mask){return (mask) & (-mask);} int pop_cnt(ll mask){return __builtin_popcountll(mask);} int ctz(ull mask){return __builtin_ctzll(mask);} int logOf(ull mask){return 63 - __builtin_clzll(mask);} mt19937_64 rng(chrono::high_resolution_clock::now().time_since_epoch().count()); ll rngesus(ll l, ll r){return l + (ull) rng() % (r - l + 1);} double rngesus_d(double l, double r){ double cur = rngesus(0, MASK(60) - 1); cur /= MASK(60) - 1; return l + cur * (r - l); } template <class T1, class T2> bool maximize(T1 &a, T2 b){ if (a < b) {a = b; return true;} return false; } template <class T1, class T2> bool minimize(T1 &a, T2 b){ if (a > b) {a = b; return true;} return false; } template <class T> void printArr(T container, string separator = " ", string finish = "\n", ostream &out = cout){ for(auto item: container) out << item << separator; out << finish; } template <class T> void remove_dup(vector<T> &a){ sort(ALL(a)); a.resize(unique(ALL(a)) - a.begin()); } int main(void){ ios::sync_with_stdio(0);cin.tie(0); cout.tie(0); clock_t start = clock(); int n, m, k; cin >> n >> m >> k; vector<int> a(n); for(int i= 0; i<n; ++i) cin >> a[i]; vector<int> b(m); for(int i = 0; i<m; ++i) cin >> b[i]; if (*min_element(ALL(a)) < k){ cout << "impossible\n"; return 0; } int barrier = n * k; int sumA = 0, sumB = 0; for(int i: a) sumA += i; for(int i: b) sumB += i; int dp[2][sumB + 1]; memset(dp, -1, sizeof dp); dp[0][0] = 0; int ans = 1e9; for(int i: b){ for(int j = 0; j <= sumB; ++j) if (dp[0][j] != -1){ maximize(dp[1][j + i], dp[0][j] + min(i, n)); } for(int j = 0; j <= sumB; ++j){ dp[0][j] = dp[1][j]; dp[1][j] = -1; if (dp[0][j] >= barrier && j >= sumA) minimize(ans, j - sumA); } } if (ans == 1e9) cout << "impossible\n"; else cout << ans << "\n"; cerr << "Time elapsed: " << clock() - start << " ms\n"; return 0; }
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