Submission #1086916

#	Time	Username	Problem	Language	Result	Execution time	Memory
1086916		daoquanglinh2007	Council (JOI23_council)	C++17	6 / 100	235 ms	8672 KiB

council

#include <bits/stdc++.h>
using namespace std;

const int NM = 3e5, MM = 20;

int N, M, msk[NM+5], occ[(1<<MM)+5], cnt[MM+5];
int f[(1<<MM)+5], g[(1<<MM)+5];

void optimize(int i, int x){
    if (f[i] == -1 || __builtin_popcount(x&i) < __builtin_popcount(f[i]&i) || (__builtin_popcount(x&i) == __builtin_popcount(f[i]&i) && x > f[i])){
        g[i] = f[i];
        f[i] = x;
        return;
    }
    if (x == f[i]) return;
    if (g[i] == -1 || __builtin_popcount(x&i) < __builtin_popcount(g[i]&i) || (__builtin_popcount(x&i) == __builtin_popcount(g[i]&i) && x > g[i])){
        g[i] = x;
    }
}

int main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

    cin >> N >> M;
    for (int i = 1; i <= N; i++){
        for (int j = 0; j < M; j++){
            char ch; cin >> ch;
            if (ch == '1'){
                msk[i] += 1<<j;
                cnt[j]++;
            }
        }
        occ[msk[i]]++;
    }
    for (int i = 0; i < (1<<M); i++){
        f[i] = (occ[i] > 0 ? i : -1);
        g[i] = -1;
    }
    for (int j = 0; j < M; j++)
        for (int i = 0; i < (1<<M); i++)
            if ((i>>j)&1){
                if (f[i-(1<<j)] != -1) optimize(i, f[i-(1<<j)]);
                if (g[i-(1<<j)] != -1) optimize(i, g[i-(1<<j)]);
            }
    for (int i = (1<<M)-1; i >= 0; i--)
        for (int j = 0; j < M; j++)
            if (((i>>j)&1) == 0){
                optimize(i, f[i+(1<<j)]);
                optimize(i, g[i+(1<<j)]);
            }
    for (int i = 1; i <= N; i++){
        int tmp = 0, res = 0;
        for (int j = 0; j < M; j++){
            if (cnt[j]-((msk[i]>>j)&1) >= N/2) res++;
            if (cnt[j]-((msk[i]>>j)&1) == N/2) tmp += (1<<j);
        }
        if (f[tmp] == msk[i] && occ[msk[i]] == 1) res -= __builtin_popcount(g[tmp]&tmp);
        else res -= __builtin_popcount(f[tmp]&tmp);

        cout << res << '\n';
    }
    return 0;
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 8
• Subtask 3: 6 / 6
• Subtask 4: 0 / 19
• Subtask 5: 0 / 15
• Subtask 6: 0 / 22
• Subtask 7: 0 / 22