답안 #1086762

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
1086762 2024-09-11T12:24:52 Z asli_bg 열대 식물원 (Tropical Garden) (IOI11_garden) C++11
0 / 100
27 ms 60504 KB
#include<bits/stdc++.h>
using namespace std;

#include "garden.h"
#include "gardenlib.h"

//#define int long long
 
#define fi first
#define se second
#define all(x) x.begin(),x.end()
#define pb push_back
 
typedef vector<int> vi;
typedef pair<int,int> pii;
typedef vector<pii> vii;
typedef vector<bool> vb;
 
#define sp <<' '<<
#define FOR(i,a) for(int i=0;i<(a);i++)
#define FORE(i,a,b) for(int i=(a);i<(b);i++)
 
#define cont(x) {for(auto el:x) cout<<el<<' ';cout<<endl;}
#define contp(x) {for(auto el:x) cout<<el.fi<<'-'<<el.se<<' ';cout<<endl;}
#define DEBUG(X) { cout << #X << " = " << (X) << endl; }
 
#define carp(x,y) (((x)%mod)*((y)%mod))%mod
#define topla(x,y) (((x)%mod)+((y)%mod))%mod
 
const int MAXN=150005;
const int MAXK=30;
 
#define mid (l+r)/2
#define endl '\n'

int n,m,p;
vii adj[MAXN];
int suc[MAXN][MAXK][3];
int cik[MAXN][MAXK][3];
int cur[MAXN];
int rt[MAXN];
vi route[MAXN];

void calc(){
    FORE(k,1,MAXK){
        FORE(nd,1,n+1){
            if(suc[nd][k-1][1]!=-1){ //1.routeu izleyerek k-1 adım gidiliyorsa
                int bir=suc[nd][k-1][1];
                suc[nd][k][1]=suc[bir][k-1][cik[nd][k-1][1]];//min edge i kullan da gel
                cik[nd][k][1]=cik[bir][k-1][cik[nd][k-1][1]];
            }

            
            if(suc[nd][k-1][2]!=-1){
                int bir=suc[nd][k-1][2];
                suc[nd][k][2]=suc[bir][k-1][cik[nd][k-1][2]];//min edge i kullan da gel
                cik[nd][k][2]=cik[bir][k-1][cik[nd][k-1][2]];
            }
        }
    }
}

void count_routes(int N, int M, int P, int R[][2], int Q, int G[])
{
    n=N;
    m=M;
    p=P;
    p++;
    memset(suc, -1, sizeof suc);
    FORE(i,1,m+1){
        int from=R[i-1][0];
        int to=R[i-1][1];
        from++;to++;
        adj[from].pb({i-1,to});
        adj[to].pb({i-1,from});
    }

    FORE(i,1,n+1){
        sort(all(adj[i]));
        while(adj[i].size()>2) adj[i].pop_back();
        
        if(adj[i].size()>=1){
            int kom=adj[i][0].se;
            //1.routu izle
            suc[i][0][1]=kom;
            if(adj[kom][0].se==i and adj[kom].size()>1){
                cik[i][0][1]=2;
                //successor i'nin hangi nodeundan devam edicem
            }
            else{
                cik[i][0][1]=1;
            }
        }

        if(adj[i].size()>=2){ //2.bir route varsa
            //2.routu izle
            int kom=adj[i][1].se;
            suc[i][0][2]=kom;
            if(adj[kom][0].se==i and adj[kom].size()>1){
                cik[i][0][2]=2;
            }
            else{
                cik[i][0][2]=1;
            }
        }

    }

    //calculate successor of each node
    calc();

    int q=Q;
    vi qq, cc;
    FOR(i,q){
        int deg=G[i];
        qq.pb(deg);
        cc.pb(deg);
    }

    sort(all(qq));

    map<int,int> cev;
    FORE(i,1,n+1){
        cur[i]=i;
        route[i].pb(i);
    }

    FORE(i,1,n+1) rt[i]=1;

    FORE(i,1,n+1){
        int once=0;
        for(auto ell:qq){
            auto el=ell;
            el-=once;

            if(el==0) continue;
            FOR(j,MAXK){
                if((1<<j)>el) break;
                if(el&(1<<j)){
                    int node=cur[i];
                    cur[i]=suc[node][j][rt[i]];
                    rt[i]=cik[node][j][rt[i]];
                    if(cur[i]==i and rt[i]==1){
                        break;
                    }
                    route[i].pb(cur[i]);
                }
            }

            int sz=route[i].size();
            if(route[i][ell%sz]==p) cev[ell]++;

            once+=el;
        }
        //cont(route[i]);
    }

    for(auto el:cc){
        answer(cev[el]);
    }
}
# 결과 실행 시간 메모리 Grader output
1 Incorrect 27 ms 60504 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 27 ms 60504 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 27 ms 60504 KB Output isn't correct
2 Halted 0 ms 0 KB -