이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#define pii pair<int, int>
#define endl '\n'
using namespace std;
int N, R, Q, SQRT_N;
const int MAX_N = 2e5 + 1;
const int MX_SQRT = 448;
const int MAX_R = 25001;
vector<int> graph[MAX_N], rgraph[MAX_N];
int sol[MX_SQRT][MAX_R];
int regions[MAX_N], reg_cnt[MAX_R], conv[MAX_R], tin[MAX_N], tout[MAX_N], cnt[MAX_R];
vector<int> sqrt_r;
void dfs(int v)
{
for (int r : sqrt_r)
sol[conv[r]][regions[v]] += cnt[conv[r]];
cnt[regions[v]]++;
for (int u : graph[v])
dfs(u);
cnt[regions[v]]--;
}
void etour(int v, int &tim)
{
rgraph[regions[v]].push_back(v);
tin[v] = tim++;
for (int u : graph[v])
etour(u, tim);
tout[v] = tim++;
}
signed main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
cin >> N >> R >> Q;
SQRT_N = sqrt(N);
cin >> regions[0];
--regions[0];
reg_cnt[regions[0]]++;
for (int i = 1; i < N; i++)
{
int v;
cin >> v >> regions[i];
--regions[i];
--v;
graph[v].push_back(i);
reg_cnt[regions[i]]++;
}
for (int i = 0; i < R; i++)
{
if (reg_cnt[i] > SQRT_N)
{
sqrt_r.push_back(i);
conv[i] = sqrt_r.size() - 1;
}
else
conv[i] = -1;
}
int tim = 0;
etour(0, tim);
dfs(0);
while (Q--)
{
int a, b;
cin >> a >> b;
--a;
--b;
if (conv[a] != -1)
{
cout << sol[conv[a]][b] << endl;
continue;
}
int res = 0;
for (int v : rgraph[a])
{
if (rgraph[b].empty())
continue;
int l = 0, r = rgraph[b].size() - 1;
int lb = -1;
while (l <= r)
{
int m = l + (r - l) / 2;
int u = rgraph[b][m];
if (tin[u] < tin[v])
l = m + 1;
else if (tout[u] > tout[v])
r = m - 1;
else
{
lb = m;
r = m - 1;
}
}
if (lb == -1)
continue;
l = 0;
r = rgraph[b].size() - 1;
int rb = -1;
while (l <= r)
{
int m = l + (r - l) / 2;
int u = rgraph[b][m];
if (tin[u] < tin[v])
l = m + 1;
else if (tout[u] > tout[v])
r = m - 1;
else
{
rb = m;
l = m + 1;
}
}
res += (rb - lb + 1);
}
cout << res << endl;
}
}
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