제출 #1086123

#제출 시각아이디문제언어결과실행 시간메모리
1086123lukasuliashviliKnapsack (NOI18_knapsack)C++17
73 / 100
5 ms1104 KiB
#include <bits/stdc++.h> using namespace std; const int N = 10005; long long v[N], w[N]; long long dp[N]; int k[N]; void binary_decompose(int idx, int n, int s) { long long value = v[idx]; long long weight = w[idx]; long long count = k[idx]; // Decompose count into powers of two for (long long i = 1; i <= count; i *= 2) { long long num = min(i, count); // Take min to avoid exceeding k[i] count -= num; // Process this number of items for (int j = s; j >= num * weight; j--) { dp[j] = max(dp[j], dp[j - num * weight] + num * value); } } // If count is still left, process the remaining items if (count > 0) { for (int j = s; j >= count * weight; j--) { dp[j] = max(dp[j], dp[j - count * weight] + count * value); } } } int main() { int s, n; cin >> s >> n; for (int i = 1; i <= n; i++) { cin >> v[i] >> w[i] >> k[i]; // v[i] = value, w[i] = weight, k[i] = max times we can take item i } // Initialize dp array fill(dp, dp + s + 1, 0); // Process each item using binary decomposition for (int i = 1; i <= n; i++) { binary_decompose(i, n, s); } cout << dp[s] << endl; return 0; }
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