Submission #1085697

#TimeUsernameProblemLanguageResultExecution timeMemory
1085697vladiliusHighway Tolls (IOI18_highway)C++17
0 / 100
11 ms2812 KiB
#include "highway.h" #include <bits/stdc++.h> using namespace std; using ll = long long; using pii = pair<int, int>; #define pb push_back #define ff first #define ss second void find_pair(int n, vector<int> U, vector<int> V, int A, int B){ int m = (int) U.size(); vector<pii> g[n + 1]; for (int i = 0; i < m; i++){ U[i]++; V[i]++; g[U[i]].pb({V[i], i}); g[V[i]].pb({U[i], i}); } vector<int> w(m); ll nl = ask(w); auto check1 = [&](int x){ fill(w.begin(), w.end(), 0); for (int i = x + 1; i < m; i++) w[i] = 1; return (ask(w) == nl); }; int l = 0, r = m - 1; while (l + 1 < r){ int k = (l + r) / 2; if (check1(k)){ r = k; } else { l = k + 1; } } if (check1(l)) r = l; int x = r; vector<bool> used(n + 1); vector<int> ed = {x}; queue<int> q({V[x], U[x]}); used[V[x]] = used[U[x]] = 1; while (!q.empty()){ int f = q.front(); q.pop(); for (auto [i, j]: g[f]){ if (used[i]) continue; used[i] = 1; q.push(i); ed.pb(j); } } auto cl = [&](){ fill(w.begin(), w.end(), 1); for (int i: ed) w[i] = 0; }; cl(); vector<pii> t[n + 1]; for (int i: ed){ t[U[i]].pb({V[i], i}); t[V[i]].pb({U[i], i}); } vector<int> d(n + 1), p(n + 1), pe(n + 1); function<void(int, int, vector<int>&, vector<int>&)> dfs = [&](int v, int pr, vector<int>& E, vector<int>& q){ q.pb(v); p[v] = pr; for (auto [i, j]: t[v]){ if (i == pr || j == x) continue; d[i] = d[v] + 1; pe[i] = j; E.pb(j); dfs(i, v, E, q); } }; vector<int> d1, d2, t1, t2; dfs(U[x], 0, d1, t1); dfs(V[x], 0, d2, t2); int dist = (int) (ask(w) / A); auto cmp = [&](int x, int y){ return (d[x] < d[y]); }; ll AA = 1LL * dist * A; auto solve = [&](int v, vector<int>& x2, vector<int> vv){ auto check = [&](int k){ fill(w.begin(), w.end(), 1); for (int i = 1; i <= k; i++){ w[pe[vv[i]]] = 0; } return (ask(w) == AA); }; sort(vv.begin(), vv.end(), cmp); int l = 0, r = (int) vv.size() - 1; while (l + 1 < r){ int k = (l + r) / 2; if (check(k)){ r = k; } else { l = k + 1; } } if (check(l)) r = l; return (vv[r] - 1); }; answer(solve(U[x], d2, t1), solve(V[x], d1, t2)); }
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