제출 #1084953

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1084953		pemguimn	운세 보기 2 (JOI14_fortune_telling2)	C++14	4 / 100	61 ms	11468 KiB

fortune_telling2

#include <bits/stdc++.h>
#define int long long
using namespace std;

const int N = 2e5 + 5, VAL = 3 * N, MAX = 4 * VAL;
int n, k, a[N], b[N], t[N], pos[N];

int ans[N];

int seg[MAX];
vector<int> val;

void upd(int id, int tl, int tr, int i, int x){
    if(i < tl || i > tr) return;
    if(tl == tr){
        seg[id] = max(seg[id], x); return;
    }
    int mid = (tl + tr) / 2;
    upd(id * 2, tl, mid, i, x), upd(id * 2 + 1, mid + 1, tr, i, x);
    seg[id] = max(seg[id * 2], seg[id * 2 + 1]);
}

int query(int id, int tl, int tr, int l, int r){
    if(r < tl || tr < l) return 0;
    if(l <= tl && tr <= r) return seg[id];
    int mid = (tl + tr) / 2;
    return max(query(id * 2, tl, mid, l, r), query(id * 2 + 1, mid + 1, tr, l, r));
}

int bit[MAX];

void upd(int x, int val){
    for(; x < MAX; x += x & -x){
        bit[x] += val;
    }
}

void upd(int l, int r, int val){
    l++, r++;
    upd(l, val), upd(r + 1, -val);
}

int query(int x){
    x++;
    int ans = 0;
    for(; x; x -= x & -x) ans += bit[x];
    return ans;
}
vector<int> p[N];
signed main(){
    ios_base::sync_with_stdio(0); cin.tie(0);

    cin >> n >> k;
    for(int i = 1; i <= n; i++) cin >> a[i] >> b[i], val.insert(val.end(), {a[i], b[i]});
    for(int i = 1; i <= k; i++) cin >> t[i], val.push_back(t[i]);

    sort(val.begin(), val.end()); val.resize(unique(val.begin(), val.end()) - val.begin());
    for(int i = 1; i <= n; i++) a[i] = lower_bound(val.begin(), val.end(), a[i]) - val.begin(), b[i] = lower_bound(val.begin(), val.end(), b[i]) - val.begin();
    for(int i = 1; i <= k; i++) t[i] = lower_bound(val.begin(), val.end(), t[i]) - val.begin();

    for(int i = 1; i <= k; i++) upd(1, 0, val.size() - 1, t[i], i);

    for(int i = 1; i <= n; i++){
        pos[i] = query(1, 0, val.size() - 1, min(a[i], b[i]), max(a[i], b[i]));
        p[pos[i]].push_back(i);
    }

    for(int i = k; i >= 0; i--){
        if(i) upd(0, t[i], 1);
        for(int x : p[i]){
            int cnt = query(max(a[x], b[x]));
            if(i == 0){
                ans[x] = (cnt & 1 ? b[x] : a[x]);
            } else{
                if(a[x] > b[x]) swap(a[x], b[x]);
                ans[x] = (cnt & 1 ? a[x] : b[x]);
            }
        }
    }

    long long res = 0;
    for(int i = 1; i <= n; i++) res += val[ans[i]];
    cout << res << '\n';
    return 0;
}

• Subtask 1: 4 / 4
• Subtask 2: 0 / 31
• Subtask 3: 0 / 65