이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <fstream>
#include <vector>
#include <queue>
#include <utility>
#include <algorithm>
#include <set>
int gs, x, q;
std::vector<std::vector<int>> adj_list;
int arr[200005];
int up[18][200005];
int depth[200005];
std::set<int> occurences1[200005]; // occurences of node i in arr
std::set<int> occurences2[200005]; // occurences of lca of any two consecutive nodes in arr
void dfs(int k, int p) {
depth[k] = depth[p]+1;
up[0][k] = p;
for (int l = 1; l < 18; l++) {
up[l][k] = up[l-1][up[l-1][k]];
}
for (const auto& i : adj_list[k]) {
if (i!=p) {
dfs(i,k);
}
}
}
int get_kth_ancestor(int node, int k) {
while (k) {
int lvl = 31-__builtin_clz(k);
node = up[lvl][node];
k ^= (1<<lvl);
}
return node;
}
int get_lca(int a, int b) {
if (depth[a]>depth[b]) {
std::swap(a,b);
}
b = get_kth_ancestor(b,depth[b]-depth[a]);
for (int lvl = 17; a != b;) {
while (lvl-1>=0&&up[lvl][a]==up[lvl][b]) {
--lvl;
}
a = up[lvl][a];
b = up[lvl][b];
}
return a;
}
int main() {
std::ios_base::sync_with_stdio(false);
std::cin.tie(NULL);
std::cout.tie(NULL);
std::cin >> gs >> x >> q;
adj_list.resize(gs+1);
for (int i = 0, a, b; i < gs-1; i++) {
std::cin >> a >> b;
adj_list[a].emplace_back(b);
adj_list[b].emplace_back(a);
}
dfs(1,0);
for (int i = 1; i <= x; i++) {
std::cin >> arr[i];
occurences1[arr[i]].emplace(i);
}
for (int i = 1; i+1 <= x; i++) {
occurences2[get_lca(arr[i],arr[i+1])].emplace(i);
}
while (q--) {
int op;
std::cin >> op;
if (op==1) {
int pos, val;
std::cin >> pos >> val;
occurences1[arr[pos]].erase(pos);
if (pos-1>=1) {
occurences2[get_lca(arr[pos-1],arr[pos])].erase(pos-1);
}
if (pos+1<=x) {
occurences2[get_lca(arr[pos],arr[pos+1])].erase(pos);
}
arr[pos] = val;
occurences1[arr[pos]].emplace(pos);
if (pos-1>=1) {
occurences2[get_lca(arr[pos-1],arr[pos])].emplace(pos-1);
}
if (pos+1<=x) {
occurences2[get_lca(arr[pos],arr[pos+1])].emplace(pos);
}
}
else {
int l, r, k;
std::cin >> l >> r >> k;
// if k itself pops up in [l, r]
auto it = occurences1[k].lower_bound(l);
if (it!=occurences1[k].end()&&*it<=r) {
std::cout << (*it) << " " << (*it) << "\n";
continue;
}
// if two consecutive occurences with lca k happen in [l, r]
it = occurences2[k].lower_bound(l);
if (it!=occurences2[k].end()&&(*it+1)<=r) {
std::cout << (*it) << " " << (*it+1) << "\n";
continue;
}
std::cout << "-1 -1\n";
}
}
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |